zoukankan      html  css  js  c++  java
  • Quicksum

     

    Quicksum

    时间限制:3000 ms  |  内存限制:65535 KB
    难度:2
     
    描述

    A checksum is an algorithm that scans a packet of data and returns a single number. The idea is that if the packet is changed, the checksum will also change, so checksums are often used for detecting transmission errors, validating document contents, and in many other situations where it is necessary to detect undesirable changes in data.

    For this problem, you will implement a checksum algorithm called Quicksum. A Quicksum packet allows only uppercase letters and spaces. It always begins and ends with an uppercase letter. Otherwise, spaces and letters can occur in any combination, including consecutive spaces.

    A Quicksum is the sum of the products of each character's position in the packet times the character's value. A space has a value of zero, while letters have a value equal to their position in the alphabet. So, A=1, B=2, etc., through Z=26. Here are example Quicksum calculations for the packets "ACM" and "MID CENTRAL":

    ACM: 1*1  + 2*3 + 3*13 = 46
    
    MID CENTRAL: 1*13 + 2*9 + 3*4 + 4*0 + 5*3 + 6*5 + 7*14 + 8*20 +
    9*18 + 10*1 + 11*12 = 650
     
    输入
    The input consists of one or more packets followed by a line containing only # that signals the end of the input. Each packet is on a line by itself, does not begin or end with a space, and contains from 1 to 300 characters.
    输出
    For each packet, output its Quicksum on a separate line in the output.
    样例输入
    ACM
    MID CENTRAL
    REGIONAL PROGRAMMING CONTEST
    ACN
    A C M
    ABC
    BBC
    #
    样例输出
    46
    650
    4690
    49
    75
    14
    15

    #include<iostream>
    #include<cstring>
    #include<cstdio>
    using namespace std;

    int main()
    {
      int str,i,k;
      char s[303];

      while(gets(s))
      {
        if(s[0]=='#')
      break;
     str=strlen(s);
     int sum=0;
     for(i=0;i<str;i++)
     {
       if(s[i]==' ') k=0; else k=(int)(s[i]-'@') ;
       sum+=(i+1)*k;
     }
     cout<<sum<<endl;
      }
      return 0;
    }

  • 相关阅读:
    文件下载并删除
    程序输出
    什么是并发
    跨站脚本攻击为什么要过滤危险字符串
    正则表达式——极速入门
    输出的为X= 1 ,Y = 0;
    Eclipse+MyEclipse安装及环境配置
    J2EE有三个开发环境级。
    TCP和UDP的区别
    asp.net2.0导出pdf文件完美解决方案(转载)
  • 原文地址:https://www.cnblogs.com/hpuwangjunling/p/2407070.html
Copyright © 2011-2022 走看看