Problem of Precision solution

question：

 InputThe first line of input gives the number of cases, T. T test cases follow, each on a separate line. Each test case contains one positive integer n. (1 <= n <= 10^9)
OutputFor each input case, you should output the answer in one line.
Sample Input

3
1
2
5

Sample Output9

97
841

#include <cstdio>

using namespace std;
const int maxx
 = 1024;
int n;
struct math {
    int s[2][2];
    math(int a = 0, int b = 0, int c = 0, int d = 0) {
        s[0][0] = a; 
        s[0][1] = b; 
        s[1][0] = c; 
        s[1][1] = d; 
    }
    math operator * (const math& c) {
       math as; for (int i = 0; i < 2; i++) 
            for (int j = 0; j < 2; j++)
                for (int k = 0; k < 2; k++)
                    as.s[i][j] = (as.s[i][j] + s[i][k] * c.s[k][j]) % maxx;
        return as;
    }
}tmp(5, 12, 2, 5);
 
math pow_mod(int k) {
    if (k == 1)
        return tmp;
    math a = pow_mod(k / 2);
    math as = a * a;
    if (k % 2)
        as = as * tmp;
    return as;
}
 
int main() {
    int cas;
    scanf("%d", &cas);
    while (cas--) {
        scanf("%d", &n); 
        math as = pow_mod(n); 
        printf("%d
", (as.s[0][0] * 2 - 1) % maxx); 
    }
    return 0;