KK's Steel
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 197 Accepted Submission(s): 90
Problem Description
Our lovely KK has a difficult mathematical problem:he has a N(1≤N≤1018)
meters steel,he will cut it into steels as many as possible,and he doesn't want any two of them be the same length or any three of them can form a triangle.
Input
The first line of the input file contains an integer T(1≤T≤10)
, which indicates the number of test cases.
Each test case contains one line including a integer N(1≤N≤1018) ,indicating the length of the steel.
Each test case contains one line including a integer N(1≤N≤1018) ,indicating the length of the steel.
Output
For each test case, output one line, an integer represent the maxiumum number of steels he can cut it into.
Sample Input
1
6
Sample Output
3
Hint
1+2+3=6 but 1+2=3 They are all different and cannot make a triangle.Source
题意: n米长的钢管切成若干段 要求每段 长度不同 且任意三段不能组成三角形 问最多能分成多少段
题解: 易发现 满足斐波那契数列
#include<iostream> #include<cstdio> #define LL __int64 using namespace std; int main() { int t; LL n; scanf("%d",&t); for(int i=1;i<=t;i++) { scanf("%I64d",&n); LL exm=1; LL ans=0; LL flag=1; while(n>=exm) { LL gg; gg=exm; ans++; n-=exm; exm+=flag; flag=gg; //cout<<flag<<" "<<exm<<endl; } printf("%I64d ",ans); } return 0; }