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  • python数据库连接

    连接数据库前,请先确认以下事项:

    已经创建了数据库 ,表及用户名,密码

    已经安装了 Python MySQLdb 模块。

    数据库连接:

    import MySQLdb
    db = MySQLdb.connect("localhost", "testuser", "test123", "TESTDB", charset='utf8' )
    cursor = db.cursor()
    cursor.execute("DROP TABLE IF EXISTS EMPLOYEE")
    sql = """CREATE TABLE EMPLOYEE (
             FIRST_NAME  CHAR(20) NOT NULL,
             LAST_NAME  CHAR(20),
             AGE INT,  
             SEX CHAR(1),
             INCOME FLOAT )"""
    cursor.execute(sql)
    db.close()

    创建数据库表:

    import MySQLdb
    db = MySQLdb.connect("localhost", "testuser", "test123", "TESTDB", charset='utf8' )
    cursor = db.cursor()
    cursor.execute("SELECT VERSION()")
    data = cursor.fetchone()
    print "Database version : %s " % data
    db.close()

    数据插入:

    import MySQLdb
    db = MySQLdb.connect("localhost", "testuser", "test123", "TESTDB", charset='utf8' )
    cursor = db.cursor()
    sql = """INSERT INTO EMPLOYEE(FIRST_NAME,
             LAST_NAME, AGE, SEX, INCOME)
             VALUES ('Mac', 'Mohan', 20, 'M', 2000)"""
    try:
       cursor.execute(sql)
       db.commit()
    except:
    db.close()

    数据查询:

    import MySQLdb
    db = MySQLdb.connect("localhost", "testuser", "test123", "TESTDB", charset='utf8' )
    cursor = db.cursor()
    sql = "SELECT * FROM EMPLOYEE 
           WHERE INCOME > %s" % (1000)
    try:
       cursor.execute(sql)
       results = cursor.fetchall()
       for row in results:
          fname = row[0]
          lname = row[1]
          age = row[2]
          sex = row[3]
          income = row[4]
          print "fname=%s,lname=%s,age=%s,sex=%s,income=%s" % 
                 (fname, lname, age, sex, income )
    except:
       print "Error: unable to fecth data"
    db.close()

    数据更新:

    import MySQLdb
    db = MySQLdb.connect("localhost", "testuser", "test123", "TESTDB", charset='utf8' )
    cursor = db.cursor()
    sql = "UPDATE EMPLOYEE SET AGE = AGE + 1 WHERE SEX = '%c'" % ('M')
    try:
       cursor.execute(sql)
       db.commit()
    except:
       db.rollback()
    db.close()

    数据删除:

    import MySQLdb
    db = MySQLdb.connect("localhost", "testuser", "test123", "TESTDB", charset='utf8' )
    cursor = db.cursor()
    sql = "DELETE FROM EMPLOYEE WHERE AGE > %s" % (20)
    try:
       cursor.execute(sql)
       db.commit()
    except:
       db.rollback()
    db.close()
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  • 原文地址:https://www.cnblogs.com/huanghuangwei/p/12044602.html
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