sql语句

--insert
insert into dbo.food ([name], remark) values ('火爆大头菜','好吃不得了')

--select
select count(*) from menu
select * from food
select * from food where [remark] like '%不得了%'

--update
update food set remark=replace(remark,'肉类产品','好吃锅包肉') 
update food set remark+='油炸' where id=1


--delete
delete food where  id=5


--关联
select * from food inner join price on food.id=price.foodid 
inner join menu on price.menuid=menu.id
where menu.id=1

select [food].[id], [food].[name], [remark],[price],[menu].[name]from food inner join price on food.id=price.foodid 
inner join menu on price.menuid=menu.id
where menu.id=1

select [food].[id], [food].[name], [remark],[price],[menu].[name]from food inner join price on food.id=price.foodid 
inner join menu on price.menuid=menu.id order by [food].[id] --升序
desc --降序


--分页
select top 3  row_number() over (order by [food].[id]) as row_no  , * from food

select * from (select top 6 row_number() over (order by [food].[id] desc) as row_no ,
[food].[id] as foodid, [food].[name] as foodname, [food].[remark] as foodremark,[price].[price] ,[menu].[name] as menuname from food inner join price on food.id=price.foodid 
inner join menu on price.menuid=menu.id )as newtable 
where row_no>2 
and row_no<4

select top 6 row_number() over (order by [foodid] desc) as row_no,* from
(select [food].[id] as foodid, [food].[name] as foodname, [food].[remark] as foodremark,[price].[price] ,[menu].[name] as menuname 
from food inner join price on food.id=price.foodid 
inner join menu on price.menuid=menu.id 
where menu.id=1)                   --显示春季价格
as hgj                             --加上row_no
 
select top 3 row_number() over (order by [id]) as row_no ,* from food order by id desc