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  • [leecode]Clone Graph

    Clone Graph

    Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.


    OJ's undirected graph serialization:

    Nodes are labeled uniquely.

    We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.

    As an example, consider the serialized graph {0,1,2#1,2#2,2}.

    The graph has a total of three nodes, and therefore contains three parts as separated by #.

    1. First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
    2. Second node is labeled as 1. Connect node 1 to node 2.
    3. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.

    Visually, the graph looks like the following:

           1
          / 
         /   
        0 --- 2
             / 
             \_/

    算法分析:

    BFS的变种,维护一个map来记录已经生成的copy node,如果已经生成,则直接从map中取就行了,否则需要new出一个新的。

    维护一个set来记录在queue中,或者已经出queue的点(其实没有必要用set的,直接可以在queue里查询的,但是考虑到效率,还是用了set,而且只记录label,空间也很省)

    代码如下:

     1 public class Solution {
     2     public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
     3         if(node == null) return null;
     4         Queue<UndirectedGraphNode> q = new LinkedList<UndirectedGraphNode>();
     5         Set<Integer> set = new HashSet<Integer>();
     6         Map<Integer,UndirectedGraphNode> map = new HashMap<Integer,UndirectedGraphNode>();
     7         set.add(node.label);
     8         q.offer(node);
     9         map.put(node.label,new UndirectedGraphNode(node.label));
    10         while(!q.isEmpty()){
    11             UndirectedGraphNode tem = q.poll();
    12             UndirectedGraphNode copy = map.get(tem.label);
    13             List<UndirectedGraphNode> neighbors = tem.neighbors;
    14             for(UndirectedGraphNode neighbor : neighbors){
    15                 if(!set.contains(neighbor.label)){
    16                     set.add(neighbor.label);
    17                     q.offer(neighbor);
    18                 }
    19                 if(!map.containsKey(neighbor.label)){
    20                     UndirectedGraphNode copyNeighbor = new UndirectedGraphNode(neighbor.label);
    21                     map.put(neighbor.label,copyNeighbor);
    22                     copy.neighbors.add(copyNeighbor);
    23                 }else{
    24                     copy.neighbors.add(map.get(neighbor.label));
    25                 }
    26             }
    27         }
    28         return map.get(node.label);
    29     }
    30 }
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  • 原文地址:https://www.cnblogs.com/huntfor/p/3935835.html
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