用JS实现点击TreeView根节点复选框全选

以下两种方法哪个不报错就用哪个。用法都是在TreeView标签中加入OnClick=""，然后引入函数名即可

第一种方法：(摘自：http://www.cnblogs.com/freeliver54/archive/2007/09/04/881024.html)

<script type ="text/javascript" >
        function postBackByObject() {
            var o = window.event.srcElement;
            if (o.tagName == "INPUT" && o.type == "checkbox") //点击treeview的checkbox是触发
            {
                DoCheck(o, 0);
            }

        }
        function DoCheck(o, panduan) {
            if (panduan == 0) {
                var d = o.id;//获得当前checkbox的id;
                var e = d.replace("CheckBox", "Nodes");//通过查看脚本信息,获得包含所有子节点div的id
                var div = window.document.getElementById(e);//获得div对象
                if (div != null) //如果不为空则表示,存在自节点
                {
                    var check = div.getElementsByTagName("INPUT");//获得div中所有的已input开始的标记
                    for (i = 0; i < check.length; i++) {
                        if (check[i].type == "checkbox") //如果是checkbox
                        {
                            check[i].checked = o.checked;//字节点的状态和父节点的状态相同,即达到全选
                        }

                    }

                }
            }
            //点子节点的时候,使父节点的状态改变,即不为全选
            {
                var divid = null;
                try {
                    divid = o.parentElement.parentElement.parentElement.parentElement.parentElement; //子节点所在的div
                }
                catch (ex) {
                    document.write(ex.description);
                }
                if (divid == null) {
                    return;
                }
                var id = divid.id.replace("Nodes", "CheckBox"); //获得根节点的id

                var checkbox = divid.getElementsByTagName("INPUT"); //获取所有子节点数
                var s = 0;
                for (i = 0; i < checkbox.length; i++) {
                    if (checkbox[i].checked) //判断有多少子节点被选中
                    {
                        s++;
                        break;
                    }
                }

                // if(s==checkbox.length) //如果全部选中 或者 选择的是另外一个根节点的子节点 ，
                if (s > 0) { // 则开始的根节点的状态仍然为选中状态
                    window.document.getElementById(id).checked = true;
                }
                else { //否则为没选中状态
                    window.document.getElementById(id).checked = false;
                }
                DoCheck(window.document.getElementById(id), 1);
            }

        }
</script>

第二种方法(摘自：http://www.jb51.net/article/21808.htm)

<script type ="text/javascript" >
 function OnTreeNodeChecked() {
            var ele = event.srcElement;
            if (ele.type == 'checkbox') {
                var childrenDivID = ele.id.replace('CheckBox', 'Nodes');
                var div = document.getElementById(childrenDivID);
                if (div != null) {
                    var checkBoxs = div.getElementsByTagName('INPUT');
                    for (var i = 0; i < checkBoxs.length; i++) {
                        if (checkBoxs[i].type == 'checkbox')
                            checkBoxs[i].checked = ele.checked;
                    }
                }
                OnTreeNodeChildChecked(ele);

            }
        }
        function OnTreeNodeChildChecked(ele) {
            //自动处理上级
            var parentDiv = ele.parentElement.parentElement.parentElement.parentElement.parentElement;
            var parentChkBox = document.getElementById(parentDiv.id.replace('Nodes', 'CheckBox'));
            if (parentChkBox != null) {
                var ChildsChkAll = true;
                var Boxs = parentDiv.getElementsByTagName('INPUT');
                for (var i = 0; i < Boxs.length; i++) {
                    if (Boxs[i].type == 'checkbox' && Boxs[i].checked == false) {
                        ChildsChkAll = false;
                    }
                }
                parentChkBox.checked = ChildsChkAll;
                OnTreeNodeChildChecked(parentChkBox);
            }
        }
</script>