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  • 洛谷P4242 树上的毒瘤

    解:首先有个套路是一条边的权值是[两端点颜色不同]。这个用树剖直接维护,支持修改。

    每次询问建虚树,查询虚树上每条边的权值。然后树形DP,用开店的方法,每个点链加链查。

      1 #include <bits/stdc++.h>
      2 
      3 #define forson(x, i) for(int i = e[x]; i; i = edge[i].nex)
      4 
      5 typedef long long LL;
      6 const int N = 100010;
      7 
      8 struct Edge {
      9     int nex, v;
     10     LL len;
     11 }edge[N << 1], EDGE[N]; int tp, TP;
     12 
     13 int e[N], top[N], fa[N], son[N], siz[N], d[N], pos[N], id[N], num, val[N], n, imp2[N];
     14 int sum[N << 2], lc[N << 2], rc[N << 2], tag[N << 2];
     15 int imp[N], K, stk[N], Top, RT, Time, E[N], vis[N], use[N], DEEP[N];
     16 LL SIZ[N], ans[N], D[N];
     17 
     18 inline void add(int x, int y) {
     19     tp++;
     20     edge[tp].v = y;
     21     edge[tp].nex = e[x];
     22     e[x] = tp;
     23     return;
     24 }
     25 
     26 /// ------------------- tree 1 -------------------------
     27 
     28 void DFS_1(int x, int f) { /// get fa son siz d
     29     fa[x] = f;
     30     siz[x] = 1;
     31     d[x] = d[f] + 1;
     32     forson(x, i) {
     33         int y = edge[i].v;
     34         if(y == f) continue;
     35         DFS_1(y, x);
     36         siz[x] += siz[y];
     37         if(siz[y] > siz[son[x]]) {
     38             son[x] = y;
     39         }
     40     }
     41     return;
     42 }
     43 
     44 void DFS_2(int x, int f) { /// get top pos id
     45     top[x] = f;
     46     pos[x] = ++num;
     47     id[num] = x;
     48     if(son[x]) DFS_2(son[x], f);
     49     forson(x, i) {
     50         int y = edge[i].v;
     51         if(y == fa[x] || y == son[x]) continue;
     52         DFS_2(y, y);
     53     }
     54     return;
     55 }
     56 
     57 /// ------------------ seg 1 ----------------------
     58 
     59 #define ls (o << 1)
     60 #define rs (o << 1 | 1)
     61 
     62 inline void pushup(int o) {
     63     lc[o] = lc[ls];
     64     rc[o] = rc[rs];
     65     sum[o] = sum[ls] + sum[rs] + (rc[ls] != lc[rs]);
     66     return;
     67 }
     68 
     69 inline void pushdown(int o) {
     70     if(tag[o] != -1) {
     71         lc[ls] = rc[ls] = tag[ls] = tag[o];
     72         lc[rs] = rc[rs] = tag[rs] = tag[o];
     73         sum[ls] = sum[rs] = 0;
     74         tag[o] = -1;
     75     }
     76     return;
     77 }
     78 
     79 #undef ls
     80 #undef rs
     81 
     82 void build(int l, int r, int o) {
     83     if(l == r) {
     84         lc[o] = rc[o] = val[id[r]];
     85         sum[o] = 0;
     86         return;
     87     }
     88     int mid = (l + r) >> 1;
     89     build(l, mid, o << 1);
     90     build(mid + 1, r, o << 1 | 1);
     91     pushup(o);
     92     return;
     93 }
     94 
     95 void change(int L, int R, int v, int l, int r, int o) {
     96     if(L <= l && r <= R) {
     97         lc[o] = rc[o] = tag[o] = v;
     98         sum[o] = 0;
     99         return;
    100     }
    101     int mid = (l + r) >> 1;
    102     pushdown(o);
    103     if(L <= mid) change(L, R, v, l, mid, o << 1);
    104     if(mid < R) change(L, R, v, mid + 1, r, o << 1 | 1);
    105     pushup(o);
    106     return;
    107 }
    108 
    109 int ask(int p, int l, int r, int o) {
    110     if(l == r) return lc[o];
    111     int mid = (l + r) >> 1;
    112     pushdown(o);
    113     if(p <= mid) return ask(p, l, mid, o << 1);
    114     else return ask(p, mid + 1, r, o << 1 | 1);
    115 }
    116 
    117 int getSum(int L, int R, int l, int r, int o) {
    118     if(L <= l && r <= R) {
    119         return sum[o];
    120     }
    121     pushdown(o);
    122     int mid = (l + r) >> 1;
    123     if(R <= mid) return getSum(L, R, l, mid, o << 1);
    124     if(mid < L) return getSum(L, R, mid + 1, r, o << 1 | 1);
    125     return getSum(L, R, l, mid, o << 1) + getSum(L, R, mid + 1, r, o << 1 | 1) + (rc[o << 1] != lc[o << 1 | 1]);
    126 }
    127 
    128 inline int lca(int x, int y) {
    129     while(top[x] != top[y]) {
    130         if(d[top[x]] < d[top[y]])
    131             y = fa[top[y]];
    132         else
    133             x = fa[top[x]];
    134     }
    135     return d[x] < d[y] ? x : y;
    136 }
    137 
    138 inline int getLen(int x, int z) {
    139     //printf("getLen %d %d 
    ", x, z);
    140     int col = ask(pos[x], 1, n, 1), ans = 0;
    141     while(top[x] != top[z]) {
    142         ans += (col != ask(pos[x], 1, n, 1));
    143         ans += getSum(pos[top[x]], pos[x], 1, n, 1);
    144         //printf("x = %d top[x] = %d col = %d  ans = %d 
    ", x, top[x], col, ans);
    145         col = ask(pos[top[x]], 1, n, 1);
    146         x = fa[top[x]];
    147     }
    148     ans += (col != ask(pos[x], 1, n, 1));
    149     //printf("%d != %d 
    ", col, ask(pos[x], 1, n, 1));
    150     ans += getSum(pos[z], pos[x], 1, n, 1);
    151     //printf("return ans = %d 
    ", ans);
    152     return ans;
    153 }
    154 
    155 inline void Change(int x, int y, int v) {
    156     while(top[x] != top[y]) {
    157         if(d[top[x]] > d[top[y]]) {
    158             change(pos[top[x]], pos[x], v, 1, n, 1);
    159             x = fa[top[x]];
    160         }
    161         else {
    162             change(pos[top[y]], pos[y], v, 1, n, 1);
    163             y = fa[top[y]];
    164         }
    165     }
    166     if(d[x] < d[y]) std::swap(x, y);
    167     change(pos[y], pos[x], v, 1, n, 1);
    168     return;
    169 }
    170 
    171 /// ------------------- tree 2 ----------------------
    172 
    173 inline void ADD(int x, int y) {
    174     TP++;
    175     EDGE[TP].v = y;
    176     EDGE[TP].len = getLen(y, x);
    177     //printf("getLen %d %d = %d 
    ", y, x, EDGE[TP].len);
    178     EDGE[TP].nex = E[x];
    179     E[x] = TP;
    180     return;
    181 }
    182 
    183 inline bool cmp(const int &a, const int &b) {
    184     return pos[a] < pos[b];
    185 }
    186 
    187 inline void work(int x) {
    188     if(vis[x] == Time) return;
    189     vis[x] = Time;
    190     D[x] = E[x] = 0;
    191     return;
    192 }
    193 
    194 inline void build_t() {
    195     TP = 0;
    196     memcpy(imp + 1, imp2 + 1, K * sizeof(int));
    197     std::sort(imp + 1, imp + K + 1, cmp);
    198     stk[Top = 1] = imp[1];
    199     work(imp[1]);
    200     for(int i = 2; i <= K; i++) {
    201         int x = imp[i], y = lca(x, stk[Top]);
    202         work(x); work(y);
    203         while(Top > 1 && d[y] <= d[stk[Top - 1]]) {
    204             ADD(stk[Top - 1], stk[Top]);
    205             Top--;
    206         }
    207         if(y != stk[Top]) {
    208             ADD(y, stk[Top]);
    209             stk[Top] = y;
    210         }
    211         stk[++Top] = x;
    212     }
    213     while(Top > 1) {
    214         ADD(stk[Top - 1], stk[Top]);
    215         Top--;
    216     }
    217     RT = stk[Top];
    218     return;
    219 }
    220 
    221 void dfs_1(int x) { /// DP 1
    222     SIZ[x] = (use[x] == Time);
    223     for(int i = E[x]; i; i = EDGE[i].nex) {
    224         int y = EDGE[i].v;
    225         dfs_1(y);
    226         SIZ[x] += SIZ[y];
    227     }
    228     return;
    229 }
    230 
    231 void dfs_2(int x) { /// DP 2
    232     if(use[x] == Time) {
    233         ans[x] = D[x];
    234     }
    235     for(int i = E[x]; i; i = EDGE[i].nex) {
    236         int y = EDGE[i].v;
    237         D[y] = D[x] + SIZ[y] * EDGE[i].len;
    238         DEEP[y] = DEEP[x] + EDGE[i].len;
    239         //printf("dfs_2 D %d = %lld * %lld = %lld 
    ", y, SIZ[y], EDGE[i].len, D[y]);
    240         dfs_2(y);
    241     }
    242     return;
    243 }
    244 
    245 inline void cal() {
    246     build_t();
    247     dfs_1(RT);
    248     DEEP[RT] = 0;
    249     dfs_2(RT);
    250     return;
    251 }
    252 
    253 int main() {
    254     memset(tag, -1, sizeof(tag));
    255     int q;
    256     scanf("%d%d", &n, &q);
    257     for(int i = 1; i <= n; i++) {
    258         scanf("%d", &val[i]);
    259     }
    260     for(int i = 1, x, y; i < n; i++) {
    261         scanf("%d%d", &x, &y);
    262         add(x, y); add(y, x);
    263     }
    264     DFS_1(1, 0);
    265     DFS_2(1, 1);
    266     build(1, n, 1);
    267 
    268     for(int i = 1, f, x, y, z; i <= q; i++) {
    269         scanf("%d%d", &f, &x);
    270         if(f == 1) {
    271             scanf("%d%d", &y, &z);
    272             Change(x, y, z);
    273         }
    274         else {
    275             Time++;
    276             K = x;
    277             for(int j = 1; j <= K; j++) {
    278                 scanf("%d", &imp2[j]);
    279                 use[imp2[j]] = Time;
    280             }
    281             cal();
    282             LL SUM = 0;
    283             for(int i = 1; i <= K; i++) {
    284                 SUM += DEEP[imp2[i]];
    285                 //printf("D %d = %lld 
    ", imp2[i], D[imp2[i]]);
    286             }
    287             //printf("SUM = %lld 
    ", SUM);
    288             for(int i = 1; i <= K; i++) {
    289                 printf("%lld ", SUM + K * DEEP[imp2[i]] - 2 * ans[imp2[i]] + K);
    290             }
    291             puts("");
    292         }
    293     }
    294     return 0;
    295 }
    AC代码
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  • 原文地址:https://www.cnblogs.com/huyufeifei/p/10505324.html
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