AIZU 0005

GCD and LCM

Time Limit : 1 sec, Memory Limit : 65536 KB
Japanese version is here

GCD and LCM

Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given a and b (0 < a, b ≤ 2,000,000,000). You can supporse that LCM(a, b) ≤ 2,000,000,000.

Input

Input consists of several data sets. Each data set contains a and b separated by a single space in a line. The input terminates with EOF.

Output

For each data set, print GCD and LCM separated by a single space in a line.

Sample Input

8 6
50000000 30000000

Output for the Sample Input

2 24
10000000 150000000

水题不解释

#include <cstdio>
#include <cstring>
#include <algorithm>
#include <iostream>

using namespace std;

typedef long long ll;

int gcd(int x,int y) {
        return y > 0 ? gcd(y,x % y) : x;
}
int main() {

        int a,b;
        while(~scanf("%d%d",&a,&b)) {
            printf("%d ",gcd(a,b));
            printf("%lld
",(ll)a / gcd(a,b) * b);
        }

}