Dump 叶子节点:
----- begin tree dump
branch: 0x1031b23 16980771 (0: nrow: 106, level: 2)
branch: 0x10556b0 17127088 (-1: nrow: 414, level: 1)
leaf: 0x1031b24 16980772 (-1: nrow: 363 rrow: 363)
0x1031b24 16进制转换为10机制 16980772
对其运用前面所介绍过的dbms_utility里的存储过程获得其文件号和数据块号，并对该数据块进行转储，其内容如下所示。可以
select dbms_utility.data_block_address_file(16980772), dbms_utility.data_block_address_block(16980772) from dual;
SQL> select dbms_utility.data_block_address_file(16980772), dbms_utility.data_block_address_block(16980772) from dual;
DBMS_UTILITY.DATA_BLOCK_ADDRESS_FILE(16980772) DBMS_UTILITY.DATA_BLOCK_ADDRESS_BLOCK(16980772)
---------------------------------------------- -----------------------------------------------
4 203556
select value from v$diag_info where name='Default Trace File';
SQL> alter system dump datafile 4 block 203556;
Leaf block dump
===============
header address 140494383000164=0x7fc765caaa64
kdxcolev 0
KDXCOLEV Flags = - - -
kdxcolok 0
kdxcoopc 0x80: opcode=0: iot flags=--- is converted=Y
kdxconco 2
kdxcosdc 0
kdxconro 363
kdxcofbo 762=0x2fa
kdxcofeo 1498=0x5da
kdxcoavs 736
kdxlespl 0
kdxlende 0
kdxlenxt 16980773=0x1031b25
kdxleprv 0=0x0
kdxledsz 0
kdxlebksz 8032
row#0[8014] flag: ------, lock: 0, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20 --199
col 1; len 6; (6): 01 03 ad 6e 00 96
row#1[7996] flag: ------, lock: 0, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20 --199
col 1; len 6; (6): 01 03 ad 6e 00 97
row#2[7978] flag: ------, lock: 0, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20
col 1; len 6; (6): 01 04 11 54 00 92
row#3[7960] flag: ------, lock: 0, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20
col 1; len 6; (6): 01 04 11 83 00 8c
row#4[7942] flag: ------, lock: 0, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20
col 1; len 6; (6): 01 04 8c a0 00 7e
row#5[7924] flag: ------, lock: 0, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20
col 1; len 6; (6): 01 04 8c a0 00 7f
row#6[7906] flag: ------, lock: 0, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20
col 1; len 6; (6): 01 05 4b 28 00 68
row#7[7888] flag: ------, lock: 0, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20
col 1; len 6; (6): 01 05 54 bf 00 7a
row#8[1534] flag: ------, lock: 0, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20
col 1; len 6; (6): 01 05 54 bf 00 7b
row#9[1552] flag: ------, lock: 0, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20
col 1; len 6; (6): 01 05 54 bf 00 7c
row#10[1516] flag: ------, lock: 2, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20
col 1; len 6; (6): 01 05 54 bf 00 7d
row#11[1498] flag: ------, lock: 2, len=18
col 0; len 8; (8): 31 39 39 20 20 20 20 20
col 1; len 6; (6): 01 05 54 bf 00 7e
DECLARE
n VARCHAR2(2000);
BEGIN
DBMS_STATS.convert_raw_value('35', n);
DBMS_OUTPUT.put_line(n);
DBMS_STATS.convert_raw_value('30', n);
DBMS_OUTPUT.put_line(n);
DBMS_STATS.convert_raw_value('30', n);
DBMS_OUTPUT.put_line(n);
DBMS_STATS.convert_raw_value('30', n);
DBMS_OUTPUT.put_line(n);
DBMS_STATS.convert_raw_value('31', n);
DBMS_OUTPUT.put_line(n);
DBMS_STATS.convert_raw_value('20', n);
DBMS_OUTPUT.put_line(n);
DBMS_STATS.convert_raw_value('20', n);
DBMS_OUTPUT.put_line(n);
DBMS_STATS.convert_raw_value('20', n);
DBMS_OUTPUT.put_line(n);
END;
col 0; len 8; (8): 31 39 39 20 20 20 20 20 --199
ol 1是rowid,01 00 0c 8f 00 00是rowid的一部分值,也是16进制的.，先要转换成2进制的，
col 1; len 6; (6): 01 03 ad 6e 00 96
00000001 00000011 10101101 01101110 00000000 10010110
16进制转换为2进制先转换为2进制:(注意前面先补足0)
然后串起来之后前10位 0000000100 表示文件号,=4 2进制转换为10进制表示4
然后是接下来的22位 0000111010110101101110表示块号,2机制转换为10进制 241006
最后面的的16位表示行号0000000010010110 2机制转换为10进制 150
SQL> select owner, segment_name, segment_type
2 from dba_extents
3 where file_id = 4
4 and 241006 between block_id and block_id + blocks - 1;
OWNER SEGMENT_NAME SEGMENT_TYPE
------------------------------ -------------------------------------------------------------------------------- ------------------
TEST TEST TABLE
SQL>
SQL> select rowid,a.* from test a where a.goodid='199';
ROWID GOODID OBJECT_NAME
-------------------------------------------------------------------------------- -------- --------------------------------------------------------------------------------
AAAVvMAAEAAA61uACW 199 aaa
AAAVvMAAEAAA61uACX 199 aaa
AAAVvMAAEAABBFUACS 199 aaa
AAAVvMAAEAABBGDACM 199 aaa
AAAVvMAAEAABIygAB+ 199 aaa
AAAVvMAAEAABIygAB/ 199 aaa
AAAVvMAAEAABUsoABo 199 aaa
AAAVvMAAEAABVS/AB6 199 aaa
AAAVvMAAEAABVS/AB7 199 aaa
AAAVvMAAEAABVS/AB8 199 aaa
AAAVvMAAEAABVS/AB9 199 aaa
AAAVvMAAEAABVS/AB+ 199 aaa
12 rows selected
SQL>
SQL> select
2 dbms_rowid.rowid_relative_fno('AAAVvMAAEAAA61uACW') fno,
3 dbms_rowid.rowid_block_number('AAAVvMAAEAAA61uACW') bkno,
4 dbms_rowid.rowid_row_number('AAAVvMAAEAAA61uACW') rno
5 from dual
6 ;
FNO BKNO RNO
---------- ---------- ----------
4 241006 150