zoukankan      html  css  js  c++  java
  • UVa 10154

    UVa 10154 - Weights and Measures


    I know, up on top you are seeing great sights, 
    But down at the bottom, we, too, should have rights. 
    We turtles can't stand it. Our shells will all crack! 
    Besides, we need food. We are starving!" groaned Mack.

    The Problem

    Mack, in an effort to avoid being cracked, has enlisted your advice as to the order in which turtles should be dispatched to form Yertle's throne. Each of the five thousand, six hundred and seven turtles ordered by Yertle has a different weight and strength. Your task is to build the largest stack of turtles possible.

    Standard input consists of several lines, each containing a pair of integers separated by one or more space characters, specifying the weight and strength of a turtle. The weight of the turtle is in grams. The strength, also in grams, is the turtle's overall carrying capacity, including its own weight. That is, a turtle weighing 300g with a strength of 1000g could carry 700g of turtles on its back. There are at most 5,607 turtles.

    Your output is a single integer indicating the maximum number of turtles that can be stacked without exceeding the strength of any one.

    Sample Input

    300 1000
    1000 1200
    200 600
    100 101

    Sample Output

    3
    
    

    迷失在幽谷中的鸟儿,独自飞翔在这偌大的天地间,却不知自己该飞往何方……

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #define INF 0x3f3f3f3f
    using namespace std;
    int f[6000];
    struct ab
    {
        int w,s;
    } a[6000];
    bool cmp(ab a,ab b)
    {
        return a.s<b.s;
    }
    int main()
    {
        int N=0;
        for(; ~scanf("%d%d",&a[N].w,&a[N].s); N++);
        sort(a,a+N,cmp);
        int M=0,i,j;
        memset(f,INF,sizeof(f));
        f[0]=0;
        for(i=0; i<N; i++)
            for(j=M; j>=0; j--)
            {
                if(a[i].s>=f[j]+a[i].w&&f[j]+a[i].w<f[j+1])
                {
                    f[j+1]=f[j]+a[i].w;
                    if(j+1>M) M=j+1;
                }
            }
        printf("%d
    ",M);
        return 0;
    }
    

  • 相关阅读:
    共享库的使用(.so)文件
    C/C++ 的宏中#和##的作用和展开
    有趣的打字训练
    libtool 创建库的工具
    vcpkg-微软开发的VC++打包工具
    Q他中的乱码再理解
    关于头文件和源文件的分别
    std::set 中内部元素有序条件删除的理解
    python 的 字节码 导入使用
    Pychar-20170301快捷键
  • 原文地址:https://www.cnblogs.com/im0qianqian/p/5989539.html
Copyright © 2011-2022 走看看