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  • HDU 1061:Rightmost Digit

    Rightmost Digit

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 43638    Accepted Submission(s): 16411


    Problem Description
    Given a positive integer N, you should output the most right digit of N^N.
     

    Input
    The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
    Each test case contains a single positive integer N(1<=N<=1,000,000,000).
     

    Output
    For each test case, you should output the rightmost digit of N^N.
     

    Sample Input
    2 3 4
     

    Sample Output
    7 6
    Hint
    In the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7. In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6.
     

    Author
    Ignatius.L
     

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    #include<stdio.h>
    int ab[25] = {0,1,4,7,6,5,6,3,6,9,0,1,6,3,6,5,6,7,4,9,0};
    int main ()
    {
        int a,n;
        scanf ("%d",&a) ;
        while (a--)
        {
            scanf ("%d",&n) ;
            printf ("%d
    ",ab[n%20] ) ;
        }
        return 0 ;
    }
    


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  • 原文地址:https://www.cnblogs.com/im0qianqian/p/5989598.html
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