[LeetCode] Jewels and Stones

You're given strings J representing the types of stones that are jewels, and S representing the stones you have.  Each character in Sis a type of stone you have.  You want to know how many of the stones you have are also jewels.

The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".

Example 1:

Input: J = "aA", S = "aAAbbbb"
Output: 3

Example 2:

Input: J = "z", S = "ZZ"
Output: 0

Note:

• S and J will consist of letters and have length at most 50.
• The characters in J are distinct.

使用set来存在J中不同字符的。

遍历S寻找出现在set中的字符并统计。

class Solution {
public:
    int numJewelsInStones(string J, string S) {
        unordered_set<char> s(J.begin(), J.end());
        int res = 0;
        for (auto& ch : S) {
            if (s.count(ch) > 0)
                res++;
        }
        return res;
    }
};
// 9 ms