题目大意:
求割点;
基本思路:
tarjan算法,套板子
代码如下:
#include<iostream>
#include<string>
#include<vector>
#include<queue>
#include<algorithm>
#include<cstdio>
#include<cstring>
#include<cmath>
using namespace std;
const int inf = 0x3f3f3f3f;
const int maxn = 110+10;
bool vis[maxn];
int dfn[maxn],low[maxn],cut[maxn];
vector<int>gra[maxn];
int cnt=0;
void cutPoint(int fa,int u){
vis[u]=true;
dfn[u]=low[u]=++cnt;
int child=0;
int sz=gra[u].size();
for(int i=0;i<sz;i++){
int v=gra[u][i];
if(v!=fa&&vis[v]){
low[u]=min(low[u],dfn[v]);
}else if(!vis[v]){
child++;
cutPoint(u,v);
low[u]=min(low[u],low[v]);
if((fa==-1&&child>1)||(fa!=-1&&low[v]>=dfn[u])){
cut[u]=1;
}
}
}
}
int main(){
int n;
while(scanf("%d",&n)==1&&n){
if(!n) break;
cnt=0;
for(int i=1;i<=n;i++){
gra[i].clear();
}
memset(vis,false,sizeof(vis));
memset(cut,0,sizeof(cut));
int u,v;
while(scanf("%d",&u)==1&&u){
while(getchar()!='
'){
scanf("%d",&v);
gra[u].push_back(v);
gra[v].push_back(u);
}
}
for(int i=1;i<=n;i++){
if(!vis[i]){
cutPoint(-1,i);
}
}
int ans=0;
for(int i=1;i<=n;i++){
if(cut[i]){
ans++;
}
}
printf("%d
",ans);
}
return 0;
}