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  • 计总与排名SUM和RANK函数


    准备一些数据:

    CREATE TABLE [dbo].[SalesPerformance](
        [ID] [int] IDENTITY(1,1) NOT NULL,
        [Salesman] NVARCHAR(30) NOT NULL,
        [OrderDate] [DATE] NULL,
        [Sell]    DECIMAL(18,2) NULL
     )
    GO
    
    
    SELECT [Salesman],[OrderDate],[Sell] FROM [dbo].[SalesPerformance]
    GO
    Source Code
    Salesman    OrderDate    Sell
    S0003    2019-05-12    23800.00
    S0008    2019-05-19    66528.00
    S0001    2019-05-05    35455.00
    S0001    2019-05-18    75220.00
    S0003    2019-05-17    33658.00
    S0041    2019-05-10    56300.00
    S0041    2019-05-11    41811.00
    S0003    2019-05-20    26309.00
    S0007    2019-05-02    41811.00
    S0022    2019-05-26    26309.00
    S0032    2019-05-20    20000.00
    S0050    2019-05-28    20000.00
    Data

    使用SUM和GROUP BY统计各个业务员的销售额:

    SELECT [Salesman] AS [业务员],MONTH([OrderDate]) AS [月份], SUM([Sell]) AS [销售量]
    FROM [dbo].[SalesPerformance]
    GROUP BY [Salesman],MONTH([OrderDate])
    Source Code

    然后使用RANK进行排名,看看谁是销售冠军,谁与谁同级:

    ;WITH [QuantityOfSale] AS
    (
        SELECT [Salesman] AS [业务员],MONTH([OrderDate]) AS [月份], SUM([Sell]) AS [销售量]
        FROM [dbo].[SalesPerformance]
        GROUP BY [Salesman],MONTH([OrderDate])
    )
    
    SELECT [业务员],[月份],[销售量],RANK() OVER( ORDER BY [销售量] DESC) [销售排名]
    FROM [QuantityOfSale]
    Source Code
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  • 原文地址:https://www.cnblogs.com/insus/p/10938336.html
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