zoukankan      html  css  js  c++  java
  • Why RootViewController's view is rotated Automatically by System when the app first loaded? 不及格的程序员

    Your app has a UIWindow, which contains your root view controller's view, which contains the button:

    • UIWindow
      • your root view
        • UIButton

    What you didn't understand is that the UIWindow rotates the user interface by applying a rotation transform to your root. Take a look at the view hierarchy when the interface is in landscape-left orientation:

    (lldb) po [[UIApp keyWindow] recursiveDescription]
    (id) $1 = 0x0922ee80 <UIWindow: 0x942c280; frame = (0 0; 768 1024); layer = <UIWindowLayer: 0x942c380>>
       | <UIView: 0x9432b30; frame = (20 0; 748 1024); transform = [0, -1, 1, 0, 0, 0]; autoresize = W+H; layer = <CALayer: 0x9432be0>>
       |    | <UIRoundedRectButton: 0x942f7a0; frame = (476 352; 73 44); opaque = NO; layer = <CALayer: 0x942f8c0>>
       |    |    | <UIGroupTableViewCellBackground: 0x94300b0; frame = (0 0; 73 44); userInteractionEnabled = NO; layer = <CALayer: 0x9430180>>
       |    |    | <UIImageView: 0x9430af0; frame = (1 1; 71 43); opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0x9431340>>
       |    |    | <UIButtonLabel: 0x94319c0; frame = (12 12; 49 19); text = 'Button'; clipsToBounds = YES; opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0x9431d10>>
     

    See how the UIWindow's subview (UIView: 0x942c380) has a transform of [0, -1, 1, 0, 0, 0]? That transform rotates your top-level view 90˚ counter-clockwise. If you rotate your device (or the simulator) to landscape-right orientation, you will see that the transform becomes [0, 1, -1, 0, 0, 0]:

    (lldb) po [[UIApp keyWindow] recursiveDescription]
    (id) $2 = 0x07436d90 <UIWindow: 0x942c280; frame = (0 0; 768 1024); layer = <UIWindowLayer: 0x942c380>>
       | <UIView: 0x9432b30; frame = (0 0; 748 1024); transform = [0, 1, -1, 0, 0, 0]; autoresize = W+H; layer = <CALayer: 0x9432be0>>
       |    | <UIRoundedRectButton: 0x942f7a0; frame = (476 352; 73 44); opaque = NO; layer = <CALayer: 0x942f8c0>>
       |    |    | <UIGroupTableViewCellBackground: 0x94300b0; frame = (0 0; 73 44); userInteractionEnabled = NO; layer = <CALayer: 0x9430180>>
       |    |    | <UIImageView: 0x9430af0; frame = (1 1; 71 43); opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0x9431340>>
       |    |    | <UIButtonLabel: 0x94319c0; frame = (12 12; 49 19); text = 'Button'; clipsToBounds = YES; opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0x9431d10>>

    When you reset the view's transform, you're losing the rotation, so the view reverts to its “default” rotation of 0˚, which is the portrait rotation.

    Adam Lockhart's answer will fix this temporarily, but if the user rotates the device, the UIWindow will reset your view's transform, losing the translation you applied.

    The correct way to handle this is to not apply your own transform to your top-level view. Give your top-level view a subview that you can transform, and put your button inside that:

    • UIWindow
      • your root view
        • your transformable view
          • UIButton
  • 相关阅读:
    组合问题的递归实现
    递归解决全排列算法
    字符串专题练习
    Linux系统目录架构
    Linux命令行文本处理工具
    Linux扩展权限
    Linux权限机制
    Linux用户基础
    Linux文件系统挂载管理
    Sensors Grouping Model for Wireless Sensor Network*
  • 原文地址:https://www.cnblogs.com/ioriwellings/p/2855894.html
Copyright © 2011-2022 走看看