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  • spark application调度机制(spreadOutApps,oneExecutorPerWorker 算法)

    1.要想明白spark application调度机制,需要回答一下几个问题:

    1.谁来调度?
    2.为谁调度?
    3.调度什么?
    3.何时调度?
    4.调度算法
    
    前四个问题可以用如下一句话里来回答:每当集群资源发生变化时(包含master主备切换),active master 进程为所有已注册的并且没有调度完毕的application调度Worker节点上的Executor进程。
    
    集群资源发生变化是什么意思呢?这里的集群资源指的主要是cores的变化,注册/移除Executor进程使得集群的freeCores变多/变少,添加/移除Worker节点使得集群的freeCores变多/变少......,所有导致集群资源发生变化的操作,都会调用schedule()重新为application和driver进行资源调度。
    
    spark提供了两种资源调度算法:spreadOutApps和非spreadOutApps。spreadOutApps算法可以手动通过SparkConf来配置,默认是使用该算法的,spreadOut算法会尽可能的将一个application 所需要的Executor进程分布在多个worker节点上,从而提高并行度,非spreadOut与之相反,他会把一个worker节点的freeCores都耗尽了才会去下一个worker节点分配。在spark1.3.1版本时基于该机制executor的实际数量以及每个executor的cpu,可能会与配置(spark-submit)的不一样
    

    2.基本概念

    每一个application至少包含以下基本属性:

    coresPerExecutor:每一个Executor进程的cpu cores个数
    memoryPerExecutor:每一个Executor进程的memory大小
    maxCores: 这个application最多需要的cpu cores个数。
    

    每一个worker至少包含以下基本属性:

    freeCores:worker 节点当前可用的cpu cores个数
    memoryFree:worker节点当前可用的memory大小。
    

    假设一个待注册的application如下:

    coresPerExecutor:2
    memoryPerExecutor:512M
    maxCores: 12
    

    这表示这个application 最多需要12个cpu cores,每一个Executor进行都要2个core,512M内存。
    假设某一时刻spark集群有如下几个worker节点,他们按照coresFree降序排列:

    Worker1:coresFree=10  memoryFree=10G
    
    Worker2:coresFree=7   memoryFree=1G
    
    Worker3:coresFree=3   memoryFree=2G
    
    Worker4:coresFree=2   memoryFree=215M
    
    Worker5:coresFree=1   memoryFree=1G
    

    其中worker5不满足application的要求:worker5.coresFree < application.coresPerExecutor
    worker4也不满足application的要求:worker4.memoryFree < application.memoryPerExecutor
    因此最终满足调度要求的worker节点只有前三个,我们将这三个节点记作usableWorkers。

    3.spreadOut算法

    先介绍spreadOut算法吧。上面已经说了,满足条件的worker只有前三个:

    Worker1:coresFree=10  memoryFree=10G
    
    Worker2:coresFree=7   memoryFree=1G
    
    Worker3:coresFree=3   memoryFree=2G
    

    第一次调度之后,worker列表如下:

    Worker1:coresFree=8  memoryFree=9.5G  assignedExecutors=1  assignedCores=2
    
    Worker2:coresFree=7  memoryFree=1G    assignedExecutors=0  assignedCores=0
    
    Worker3:coresFree=3  memoryFree=2G    assignedExecutors=0  assignedCores=0
    
    totalExecutors:1,totalCores=2
    
    可以发现,worker1的coresFree和memoryFree都变小了而worker2,worker3并没有发生改变,这是因为我们在worker1上面分配了一个Executor进程(这个Executor进程占用2个cpu cores,512M memory)而没有在workre2和worker3上分配。
    

    接下来继续循环,开始去worker2上分配:

    Worker1:coresFree=8  memoryFree=9.5G      assignedExecutors=1  assignedCores=2
    
    Worker2:coresFree=5  memoryFree=512M      assignedExecutors=1  assignedCores=2
    
    Worker3:coresFree=3  memoryFree=2G        assignedExecutors=0  assignedCores=0
    
    totalExecutors:2,totalCores=4
    
    此时已经分配了2个Executor进程,4个core。
    

    接下来去worker3上分配:

    Worker1:coresFree=8  memoryFree=9.5G      assignedExecutors=1  assignedCores=2
    
    Worker2:coresFree=5  memoryFree=512M      assignedExecutors=1  assignedCores=2
    
    Worker3:coresFree=1  memoryFree=1.5G      assignedExecutors=1  assignedCores=2
    
    totalExecutors:3,totalCores=6
    

    接下来再去worker1分配,然后worker2...依此类推...以round-robin方式分配,由于worker3.coresFree < application.coresPerExecutor,不会在它上面分配资源了:

    Worker1:coresFree=6  memoryFree=9.0G      assignedExecutors=2  assignedCores=4
    
    Worker2:coresFree=5  memoryFree=512M      assignedExecutors=1  assignedCores=2
    
    Worker3:coresFree=1  memoryFree=1.5G      assignedExecutors=1  assignedCores=2
    
    totalExecutors:4,totalCores=8
    

    Worker1:coresFree=6  memoryFree=9.0G      assignedExecutors=2  assignedCores=4
    
    Worker2:coresFree=3  memoryFree=0M        assignedExecutors=2  assignedCores=4
    
    Worker3:coresFree=1  memoryFree=1.5G      assignedExecutors=1  assignedCores=2
    
    totalExecutors:5,totalCores=10
    

    此时worker2也不满足要求了:worker2.memoryFree < application.memoryPerExecutor
    因此,下一次分配就去worker1上了:

    Worker1:coresFree=4  memoryFree=8.5G      assignedExecutors=3  assignedCores=6
    
    Worker2:coresFree=3  memoryFree=0M        assignedExecutors=2  assignedCores=4
    
    Worker3:coresFree=1  memoryFree=1.5G      assignedExecutors=1  assignedCores=2
    
    totalExecutors:6,totalCores=12
    

    ok,由于已经分配了12个core,达到了application的要求,所以不在为这个application调度了。

    4.非spreadOut算法

    那么非spraadOut算法呢?他是逮到一个worker如果不把他的资源耗尽了是不会放手的:

    Worker1:coresFree=8  memoryFree=9.5G  assignedExecutors=1  assignedCores=2
    
    Worker2:coresFree=7  memoryFree=1G    assignedExecutors=0  assignedCores=0
    
    Worker3:coresFree=3  memoryFree=2G    assignedExecutors=0  assignedCores=0
    
    totalExecutors:1,totalCores=2
    

    Worker1:coresFree=6  memoryFree=9.0G  assignedExecutors=2  assignedCores=4
    
    Worker2:coresFree=7  memoryFree=1G    assignedExecutors=0  assignedCores=0
    
    Worker3:coresFree=3  memoryFree=2G    assignedExecutors=0  assignedCores=0
    
    totalExecutors:2,totalCores=4
    

    Worker1:coresFree=4  memoryFree=8.5    assignedExecutors=3  assignedCores=6
    
    Worker2:coresFree=7  memoryFree=1G     assignedExecutors=0  assignedCores=0
    
    Worker3:coresFree=3  memoryFree=2G     assignedExecutors=0  assignedCores=0
    
    totalExecutors:3,totalCores=6
    

    Worker1:coresFree=2   memoryFree=8.0G  assignedExecutors=4  assignedCores=8
    
    Worker2:coresFree=7   memoryFree=1G    assignedExecutors=0  assignedCores=0
    
    Worker3:coresFree=3   memoryFree=2G    assignedExecutors=0  assignedCores=0
    
    totalExecutors:4,totalCores=8
    

    Worker1:coresFree=0   memoryFree=7.5G  assignedExecutors=5  assignedCores=10
    
    Worker2:coresFree=7   memoryFree=1G    assignedExecutors=0  assignedCores=0
    
    Worker3:coresFree=3   memoryFree=2G    assignedExecutors=0  assignedCores=0
    
    totalExecutors:5,totalCores=10
    

    当worker1的coresfree已经耗尽了。由于application需要12个core,而这里才分配了10个,所以还要继续往下分配:

    Worker1:coresFree=0   memoryFree=7.5G      assignedExecutors=5  assignedCores=10
    
    Worker2:coresFree=5   memoryFree=512G      assignedExecutors=1  assignedCores=2
    
    Worker3:coresFree=3   memoryFree=2G        assignedExecutors=0  assignedCores=0
    
    totalExecutors:6,totalCores=12
    

    ok,最终分配来12个core,满足了application的要求。
    对比:

    spreadOut算法中,是以round-robin方式,轮询的在worker节点上分配Executor进程,即以如下序列分配:worker1,worker2... ... worker n,worker1... .... worker n
    
    非spreadOut算法中,逮者一个worker就不放手,直到满足一下条件之一:
    worker.freeCores < application.coresPerExecutor 或者 worker.memoryFree<application.memoryPerExecutor。
    

    在上面两个例子中,虽然最终都分配了6个Executor进程和12个core,但是spreadOut方式下,6个Executor进程分散在不同的worker节点上,充分利用了spark集群的worker节点,而非spreadOut方式下,只在worker1和worker2上分配了Executor进程,并没有充分利用spark worker节点。

    5.小插曲,spreadOut + oneExecutorPerWorker 算法

    spark还有一个叫做”oneExecutorPerWorker“机制,即一个worker上启动一个Executor进程,下面只是简单的说一下得了:

    Worker1:coresFree=8   memoryFree=9.5G  assignedExecutors=1  assignedCores=2
    
    Worker2:coresFree=7   memoryFree=1G    assignedExecutors=0  assignedCores=0
    
    Worker3:coresFree=3   memoryFree=2G    assignedExecutors=0  assignedCores=0
    
    totalExecutors:1,totalCores=2
    

    Worker1:coresFree=8   memoryFree=9.5G      assignedExecutors=1  assignedCores=2
    
    Worker2:coresFree=5   memoryFree=512M      assignedExecutors=1  assignedCores=2
    
    Worker3:coresFree=3   memoryFree=2G        assignedExecutors=0  assignedCores=0
    
    totalExecutors:2,totalCores=4
    

    Worker1:coresFree=8   memoryFree=9.5G      assignedExecutors=1  assignedCores=2
    
    Worker2:coresFree=5   memoryFree=512M      assignedExecutors=1  assignedCores=2
    
    Worker3:coresFree=1   memoryFree=1.5G      assignedExecutors=1  assignedCores=2
    
    totalExecutors:3,totalCores=6
    

    Worker1:coresFree=6   memoryFree=9.0G      assignedExecutors=1  assignedCores=4
    
    Worker2:coresFree=3   memoryFree=512M      assignedExecutors=1  assignedCores=2
    
    Worker3:coresFree=1   memoryFree=1.5G      assignedExecutors=1  assignedCores=2
    
    totalExecutors:3,totalCores=8
    

    Worker1:coresFree=6  memoryFree=9.0G      assignedExecutors=1  assignedCores=4
    
    Worker2:coresFree=2   memoryFree=0   M     assignedExecutors=1  assignedCores=4
    
    Worker3:coresFree=1   memoryFree=1.5G     assignedExecutors=1  assignedCores=2
    
    totalExecutors:3,totalCores=10
    

    Worker1:coresFree=4  memoryFree=9.5G      assignedExecutors=1  assignedCores=6
    
    Worker2:coresFree=2   memoryFree=0   M     assignedExecutors=1  assignedCores=4
    
    Worker3:coresFree=1   memoryFree=1.5G     assignedExecutors=1  assignedCores=2
    
    totalExecutors:3,totalCores=12
    

    spreadOut和oneExecutorPerWorker对比发现,唯一的不同就是Executor进程的数量,一个是6,一个是3。

    这里在额外扩展一下,假设application的maxCores=14,而不是12,那么接着上面那个worker列表来:

    Worker1:coresFree=4  memoryFree=9.5G      assignedExecutors=1  assignedCores=6
    
    Worker2:coresFree=0   memoryFree=0M     assignedExecutors=1  assignedCores=6
    
    Worker3:coresFree=1   memoryFree=1.5G     assignedExecutors=1  assignedCores=2
    
    totalExecutors:3,totalCores=12
    

    虽然worker2.memoryFree=0,但是仍然可以继续在他上面分配core,因为onExecutorPerWorker机制不检查内存的限制。

    6.源码实现

    在初始化SparkContext时其中要点之一是:taskScheduler如何注册application,及executor如何反向注册。
    在sc中会调用createTaskScheduler(),createTaskScheduler()创建完成后会调用scheduler.start()方法在刚方法中会调用backend.start()方法,最终会通过clientActor()调用registerWithMaster()来注册Application
    image_1bpssmfvi1aihlp91m3ocfo110um.png-110.3kB

    coresrcmainscalaorgapachesparkdeploymasterMaster.scala中的消息接收方法override def receive: PartialFunction[Any, Unit]中使用匹配模式接收客户端中发送来的消息

        case RegisterApplication(description, driver) => {
          // TODO Prevent repeated registrations from some driver
          //standby master不调度
    
          if (state == RecoveryState.STANDBY) {
            // ignore, don't send response
          } else {
            logInfo("Registering app " + description.name)
            // 用ApplicationDescription创建ApplicationInfo
            val app = createApplication(description, driver)
            // 注册app,即将其加入到waitingApps中
            registerApplication(app)
            logInfo("Registered app " + description.name + " with ID " + app.id)
            // 将app加入持久化引擎,主要是为了故障恢复
            persistenceEngine.addApplication(app)
            // 向driver反向注册其实是发送RegisteredApplication消息给StandaloneSchedulerBackend的
            // StandaloneAppClient的ClientEndpoint表明master已经注册了这个app
            driver.send(RegisteredApplication(app.id, self))
            // 为waitingApps中的app调度资源
            schedule()
          }
        }
    
     /**
       * Schedule the currently available resources among waiting apps. This method will be called
       * every time a new app joins or resource availability changes.
       */
      // 调用schedule()从所有可用的worker中找出可以运行该driver的worker,然后将driver和worker建立联系,然后启动driver
    private def schedule() {
    // 如果说master 的状态不是ALIVE的话就直接返回,也就是说master standby是不会对Application等资源进行调度
    if (state != RecoveryState.ALIVE) { return }
    
    // First schedule drivers, they take strict precedence over applications
    // Randomization helps balance drivers
    // Random.shuffle的原理就是对传入的集合的元素进行随机的打乱
    // 取出workers中所有之前注册上来的worker,进行过滤,必须是状态为ALIVE的worker
    val shuffledAliveWorkers = Random.shuffle(workers.toSeq.filter(_.state == WorkerState.ALIVE))
    val numWorkersAlive = shuffledAliveWorkers.size
    var curPos = 0
    // 首先,调度driver,为什么要调度?什么情况下会注册driver?并导致driver会被调度
    // 其实只有用yarn-cluster模式提交的时候,才会注册driver;因为standalone client和yarn-client模式,都会在本地直接
    // 启动driver,而不会来注册driver,就更不可能让master调度driver了
    // driver的调度机制
    // 遍历waitingDrivers的ArrayBuffer
    for (driver <- waitingDrivers.toList) { // iterate over a copy of waitingDrivers
      // We assign workers to each waiting driver in a round-robin fashion. For each driver, we
      // start from the last worker that was assigned a driver, and continue onwards until we have
      // explored all alive workers.
      var launched = false
      var numWorkersVisited = 0
      // 只要还有活着的Workers就继续遍历,而且当前这个driver还没有启动,即launched为false
      while (numWorkersVisited < numWorkersAlive && !launched) {
        val worker = shuffledAliveWorkers(curPos)
        numWorkersVisited += 1
        // 如果当前的这个worker的空闲内存量大于等于driver需要的内存
        // 并且worker的空闲cpu数量,大于等于driver需要的cpu数量
        if (worker.memoryFree >= driver.desc.mem && worker.coresFree >= driver.desc.cores) {
          // 启动driver
          launchDriver(worker, driver)
          // 并将driver从waitingDrivers队列中移除
          waitingDrivers -= driver
          launched = true
        }
        curPos = (curPos + 1) % numWorkersAlive
      }
     }
     // 启动所有在worker上的executor --- 即为application调度资源
     startExecutorsOnWorkers()
    }
    
      /**
       * Schedule and launch executors on workers
       */
      private def startExecutorsOnWorkers(): Unit = {
        // Right now this is a very simple FIFO scheduler. We keep trying to fit in the first app
        // in the queue, then the second app, etc.
        // 为waitingApps中的app调度资源,app.coresLeft是app还有多少core没有分配
    
        for (app <- waitingApps if app.coresLeft > 0) {
          val coresPerExecutor: Option[Int] = app.desc.coresPerExecutor
          // Filter out workers that don't have enough resources to launch an executor
          // 筛选出状态为ALIVE并且这个worker剩余内存,剩余core都大于等于app的要求,然后按照coresFree降序排列
    
          val usableWorkers = workers.toArray.filter(_.state == WorkerState.ALIVE)
            .filter(worker => worker.memoryFree >= app.desc.memoryPerExecutorMB &&
              worker.coresFree >= coresPerExecutor.getOrElse(1))
            .sortBy(_.coresFree).reverse
          //在usableWorkers上为app分配Executor
          val assignedCores = scheduleExecutorsOnWorkers(app, usableWorkers, spreadOutApps)
    
          // Now that we've decided how many cores to allocate on each worker, let's allocate them
          // 在worker上启动Executor进程
    
          for (pos <- 0 until usableWorkers.length if assignedCores(pos) > 0) {
            allocateWorkerResourceToExecutors(
              app, assignedCores(pos), coresPerExecutor, usableWorkers(pos))
          }
        }
      }
    

    这个方法做了如下事情:

     1.筛选出可用的worker,即usableWorkers,如果一个worker满足以下所有条件,那么这个worker就被添加到usableWorkers中:
       Alive
       worker.memoryFree >= app.desc.memoryPerExecutorMB
       worker.coresFree >= coresPerExecutor
    
     2.assignedCores是一个数组,assignedCores[i]里面存储了需要在usableWorkers[i]上分配的core个数,譬如如果assingedCores[1]=2,那么就需要在usableWorkers[1]上分配2个core。
    

    spreadOutApps算法的具体实现如下代码:

      /**
       * Schedule executors to be launched on the workers.
       * Returns an array containing number of cores assigned to each worker.
       *
       * There are two modes of launching executors. The first attempts to spread out an application's
       * executors on as many workers as possible, while the second does the opposite (i.e. launch them
       * on as few workers as possible). The former is usually better for data locality purposes and is
       * the default.
       *
       * The number of cores assigned to each executor is configurable. When this is explicitly set,
       * multiple executors from the same application may be launched on the same worker if the worker
       * has enough cores and memory. Otherwise, each executor grabs all the cores available on the
       * worker by default, in which case only one executor may be launched on each worker.
       *
       * It is important to allocate coresPerExecutor on each worker at a time (instead of 1 core
       * at a time). Consider the following example: cluster has 4 workers with 16 cores each.
       * User requests 3 executors (spark.cores.max = 48, spark.executor.cores = 16). If 1 core is
       * allocated at a time, 12 cores from each worker would be assigned to each executor.
       * Since 12 < 16, no executors would launch [SPARK-8881].
       */
      private def scheduleExecutorsOnWorkers(
          app: ApplicationInfo,
          usableWorkers: Array[WorkerInfo],
          spreadOutApps: Boolean): Array[Int] = {
        val coresPerExecutor = app.desc.coresPerExecutor
        val minCoresPerExecutor = coresPerExecutor.getOrElse(1)
        val oneExecutorPerWorker = coresPerExecutor.isEmpty
        val memoryPerExecutor = app.desc.memoryPerExecutorMB
        val numUsable = usableWorkers.length
        val assignedCores = new Array[Int](numUsable) // Number of cores to give to each worker
        val assignedExecutors = new Array[Int](numUsable) // Number of new executors on each worker
        var coresToAssign = math.min(app.coresLeft, usableWorkers.map(_.coresFree).sum)
    
        /** Return whether the specified worker can launch an executor for this app. */
        //是否可以在一个worker上分配Executor
        def canLaunchExecutor(pos: Int): Boolean = {
          val keepScheduling = coresToAssign >= minCoresPerExecutor
          val enoughCores = usableWorkers(pos).coresFree - assignedCores(pos) >= minCoresPerExecutor
    
          // If we allow multiple executors per worker, then we can always launch new executors.
          // Otherwise, if there is already an executor on this worker, just give it more cores.
          val launchingNewExecutor = !oneExecutorPerWorker || assignedExecutors(pos) == 0
          if (launchingNewExecutor) {
            //在这里,需要检查worker的空闲core和内存是否够用
            val assignedMemory = assignedExecutors(pos) * memoryPerExecutor
            val enoughMemory = usableWorkers(pos).memoryFree - assignedMemory >= memoryPerExecutor
            val underLimit = assignedExecutors.sum + app.executors.size < app.executorLimit
            keepScheduling && enoughCores && enoughMemory && underLimit
          } else {
            // We're adding cores to an existing executor, so no need
            // to check memory and executor limits
            //尤其需要注意的是,oneExecutorPerWorker机制下,不检测内存限制,很重要。
            keepScheduling && enoughCores
          }
        }
    
        // Keep launching executors until no more workers can accommodate any
        // more executors, or if we have reached this application's limits
        var freeWorkers = (0 until numUsable).filter(canLaunchExecutor)
        while (freeWorkers.nonEmpty) {
          freeWorkers.foreach { pos =>
            var keepScheduling = true
            while (keepScheduling && canLaunchExecutor(pos)) {
              //要分配的cores
              coresToAssign -= minCoresPerExecutor
              //已分配的cores
              assignedCores(pos) += minCoresPerExecutor
    
              // If we are launching one executor per worker, then every iteration assigns 1 core
              // to the executor. Otherwise, every iteration assigns cores to a new executor.
              //一个worker只启动一个Executor
              if (oneExecutorPerWorker) {
                assignedExecutors(pos) = 1
              } else {
                assignedExecutors(pos) += 1
              }
    
              // Spreading out an application means spreading out its executors across as
              // many workers as possible. If we are not spreading out, then we should keep
              // scheduling executors on this worker until we use all of its resources.
              // Otherwise, just move on to the next worker.
              //如果没有开启spreadOUt算法,就一直在一个worker上分配,直到不能再分配为止。
    
              if (spreadOutApps) {
                keepScheduling = false
              }
            }
          }
          freeWorkers = freeWorkers.filter(canLaunchExecutor)
        }
        assignedCores
      }
    
      /**
       * Allocate a worker's resources to one or more executors.
       * @param app the info of the application which the executors belong to
       * @param assignedCores number of cores on this worker for this application
       * @param coresPerExecutor number of cores per executor
       * @param worker the worker info
       */
      private def allocateWorkerResourceToExecutors(
          app: ApplicationInfo,
          assignedCores: Int,
          coresPerExecutor: Option[Int],
          worker: WorkerInfo): Unit = {
        // If the number of cores per executor is specified, we divide the cores assigned
        // to this worker evenly among the executors with no remainder.
        // Otherwise, we launch a single executor that grabs all the assignedCores on this worker.
        //计算要创建多少个Executor进程,默认值是1.
    
        val numExecutors = coresPerExecutor.map { assignedCores / _ }.getOrElse(1)
        val coresToAssign = coresPerExecutor.getOrElse(assignedCores)
        for (i <- 1 to numExecutors) {
          val exec = app.addExecutor(worker, coresToAssign)
          //真正的启动Executor进程了。
          launchExecutor(worker, exec)
          app.state = ApplicationState.RUNNING
        }
      }
    
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  • 原文地址:https://www.cnblogs.com/ios1988/p/7515484.html
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