Invert a binary tree.
4 / 2 7 / / 1 3 6 9
to
4 / 7 2 / / 9 6 3 1
Notice: Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.
Solution: recursion
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* invertTree(TreeNode* root) { if(root==NULL) return NULL; else{ TreeNode *newleft=invertTree(root->right); TreeNode *newright=invertTree(root->left); root->left=newleft; root->right=newright; return root; } } };