zoukankan      html  css  js  c++  java
  • String to Integer (atoi)

    Implement atoi to convert a string to an integer.

    Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.

    Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.

    Requirements for atoi:

    The function first discards as many whitespace characters as necessary until the first non-whitespace character is found. Then, starting from this character, takes an optional initial plus or minus sign followed by as many numerical digits as possible, and interprets them as a numerical value.

    The string can contain additional characters after those that form the integral number, which are ignored and have no effect on the behavior of this function.

    If the first sequence of non-whitespace characters in str is not a valid integral number, or if no such sequence exists because either str is empty or it contains only whitespace characters, no conversion is performed.

    If no valid conversion could be performed, a zero value is returned. If the correct value is out of the range of representable values, INT_MAX (2147483647) or INT_MIN (-2147483648) is returned.

     1 class Solution {
     2 public:
     3     int atoi(const char *str) {
     4         long long m=0;//long long 判断溢出
     5         int n=0,flag1=0,flag2=0,i=0;//flag1,flag2 对'+','-' 计数,i是总数,符号超过1个 出错 
     6         while(*str&&*str==' ')
     7             ++str;
     8         while(*str=='+'||*str == '-'){
     9             if(*str =='+'){
    10                 ++flag1;
    11                 ++i;
    12                 ++str;
    13             }else{
    14                 ++flag2;
    15                 ++i;
    16                 ++str;
    17             }
    18         }
    19         while(*str>47&&*str<58){
    20             n = *str -'0';
    21             m *=10;
    22             m += n;
    23             ++str;
    24         }
    25         if(i>1)
    26             m= 0;
    27         else if(flag2==1){
    28             m *= -1;
    29         }
    30         if(m>2147483647)
    31             m = 2147483647;
    32         else if(m < -2147483648)
    33             m = -2147483648;
    34         return m;
    35     }
    36 };
  • 相关阅读:
    如何进行shell脚本正确性测试
    linux 重命名文件和文件夹
    linux 下 `dirname $0`
    五句话搞定JavaScript作用域
    Javascrpt
    css
    HTML
    python之sqlalchemy
    Python之路【第九篇】:Python操作 RabbitMQ、Redis、Memcache、SQLAlchemy
    Python之路【第八篇】:堡垒机实例以及数据库操作
  • 原文地址:https://www.cnblogs.com/ittinybird/p/4083092.html
Copyright © 2011-2022 走看看