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  • Wooden Sticks_贪心

    Time Limit: 1000MS   Memory Limit: 10000K
    Total Submissions: 21886   Accepted: 9341

    Description

    There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows: 
    (a) The setup time for the first wooden stick is 1 minute. 
    (b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l' and weight w' if l <= l' and w <= w'. Otherwise, it will need 1 minute for setup. 
    You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are ( 9 , 4 ) , ( 2 , 5 ) , ( 1 , 2 ) , ( 5 , 3 ) , and ( 4 , 1 ) , then the minimum setup time should be 2 minutes since there is a sequence of pairs ( 4 , 1 ) , ( 5 , 3 ) , ( 9 , 4 ) , ( 1 , 2 ) , ( 2 , 5 ) .

    Input

    The input consists of T test cases. The number of test cases (T) is given in the first line of the input file. Each test case consists of two lines: The first line has an integer n , 1 <= n <= 5000 , that represents the number of wooden sticks in the test case, and the second line contains 2n positive integers l1 , w1 , l2 , w2 ,..., ln , wn , each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one or more spaces.

    Output

    The output should contain the minimum setup time in minutes, one per line.

    Sample Input

    3 
    5 
    4 9 5 2 2 1 3 5 1 4 
    3 
    2 2 1 1 2 2 
    3 
    1 3 2 2 3 1 
    

    Sample Output

    2
    1
    3
    #include<iostream>
    #include<stdio.h>
    #include<string.h>
    #include<algorithm>
    #include<stdlib.h>
    #include<queue>
    using namespace std;
    struct node
    {
        int l,w;
    } a[5050];
    bool operator <(node a,node b)
    {
        if(a.l==b.l) return a.w<b.w;
        else return a.l<b.l;
    }
    int vis[5050],k;
    int main()
    {
        int t;
        cin>>t;
        while(t--)
        {
            int n;
            cin>>n;
            memset(vis,0,sizeof(vis));
            for(int i=1; i<=n; i++)
            {
                cin>>a[i].l>>a[i].w;
            }
            node tt;
            sort(a,a+n);
            k=0;
            for(int i=1; i<=n; i++)
            {
                tt.w=a[i].w;
                if(!vis[i])
                {
                    for(int j=i+1; j<=n; j++)
                    {
                          if(tt.w<=a[j].w&&!vis[j])
                          {
                              vis[j]=1;
                              tt.w=a[j].w;
                          }
                    }
                    k++;
                }
            }
            cout<<k<<endl;
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/iwantstrong/p/5795632.html
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