ZOJ Problem Set

ZOJ Problem Set - 1029

Moving Tables

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Time Limit: 2 Seconds                                     Memory Limit: 65536 KB                            

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The famous ACM (Advanced Computer Maker) Company has rented a floor of a building   whose shape is in the following figure.

The floor has 200 rooms each on the north side and south side along the corridor.   Recently the Company made a plan to reform its system. The reform includes moving a  lot of tables between rooms. Because the corridor is narrow and all the tables are big,  only one table can pass through the corridor. Some plan is needed to make the moving  efficient. The manager figured out the following plan: Moving a table from a room to  another room can be done within 10 minutes. When moving a table from room i to room j,  the part of the corridor between the front of room i and the front of room j is used.  So, during each 10 minutes, several moving between two rooms not sharing the same part  of the corridor will be done simultaneously. To make it clear the manager illustrated  the possible cases and impossible cases of simultaneous moving.

  For each room, at most one table will be either moved in or moved out. Now,   the manager seeks out a method to minimize the time to move all the tables.  Your job is to write a program to solve the manager��s problem.


Input

  The input consists of T test cases. The number of test cases ) (T is given in   the first line of the input. Each test case begins with a line containing  an integer N , 1<=N<=200 , that represents the number of tables to move.  Each of the following N lines contains two positive integers s and t, representing   that a table is to move from room number s to room number t (each room number   appears at most once in the N lines). From the N+3-rd line, the remaining test  cases are listed in the same manner as above.

Output

  The output should contain the minimum time in minutes to complete the moving,   one per line.


Sample Input

  3
  4
  10 20
  30 40
  50 60
  70 80
  2
  1 3
  2 200
  3
  10 100
  20 80
  30 50

  Output for the Sample Input

10
  20
  30

 画线数层数

#include<iostream>
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
int main()
{
	int cas;
	cin>>cas;
	while(cas--)
	{
		int n;
		cin>>n;
		int from[202];
		int to[202];
		for(int i=0;i<n;i++)
		{
			int t1,t2;
			cin>>t1>>t2;
			if(t1>t2)swap(t1,t2);
			if(t1%2==0)from[i]=t1/2;
			else from[i]=(t1+1)/2;
			if(t2%2==0)to[i]=t2/2;
			else to[i]=(t2+1)/2;
		}
		int count[202];
		memset(count,0,sizeof(count));
		for(int i=0;i<n;i++)
		{
			for(int j=from[i];j<=to[i];j++)
			{
				count[j]++;
			}
		}
		int max=0;
		for(int i=0;i<202;i++)
		{
			if(max<count[i])max=count[i];
		}
		cout<<max*10<<endl;
	}
}