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  • HDU_1143_tri tiling

    Tri Tiling

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 2834    Accepted Submission(s): 1603


    Problem Description
    In how many ways can you tile a 3xn rectangle with 2x1 dominoes? Here is a sample tiling of a 3x12 rectangle.

     
    Input
    Input consists of several test cases followed by a line containing -1. Each test case is a line containing an integer 0 ≤ n ≤ 30. 
     
    Output
    For each test case, output one integer number giving the number of possible tilings. 
     
    Sample Input
    2 8 12 -1
     
    Sample Output
    3 153 2131
     

     参考:http://blog.csdn.net/chaoojie/article/details/8860935

    当dp[i] 划分成 2 和 i-2 后,再划分成 4和i-4时,4的部分,不能再划分成2 , 2 组合,这样就会和前面的2 和i-2 重复,同样,划分过2 ,i-2 以及 4, i-4 后,再划分 6, i-6时,也不能划分成 2,2,2 以及 2, 4或 4, 2,同理,划分成8, i-8....

    把 4, 6, 8.... 看成一整块,就有下图两种情况(正着,倒着)

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    using namespace std;
    int main()
    {
        int dp[35];
        int t;
        dp[0]=1;
        dp[1]=0;
        dp[2]=3;
        for(int i=3;i<=30;i++)
        {
            if(i%2)
            {
                dp[i]=0;
                continue;
            }
            dp[i]=dp[2]*dp[i-2];
            for(int j=i-4;j>=0;j-=2)
                dp[i]+=2*dp[j];
        }
        while(scanf("%d",&t)&&t!=-1)
        {
            cout<<dp[t]<<endl;
        }
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/jasonlixuetao/p/4707552.html
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