zoukankan      html  css  js  c++  java
  • 代码练习

    #1、使用while循环输入 1 2 3 4 5 6 8 9 10
    #方法一:
    # count = 1
    # flag = True
    # while flag:
    # if count == 7:
    # print('')
    # count += 1
    # print(count)
    # count = count + 1 # count += 1
    # if count == 11:
    # flag = False

    #方法二:
    # count = 1
    # flag = True
    # while flag:
    # # print(count)
    # if count == 7:
    # print('')
    # else:print(count)
    # count = count + 1 # count += 1
    # if count == 11:
    # flag = False

    #方法三:
    # count = 1
    # while count < 11:
    # if count == 7:
    # print('')
    # else:print(count)
    # count = count + 1 # count += 1
    count = 1
    while count < 10:
        count += 1
        if count == 7
            continue
        else:
            print(count)
    
    
    


    #2、求1-100的所有数的和

    # count = 1
    # sum = 0
    # while count < 101:
    # # sum2 = count
    # sum = sum + count # sum += count
    # count = count + 1
    # print(sum)

    #3、输出 1-100 内的所有奇数
    #1,3,5,7,9.。。。。。
    #方法一:
    # count = 1
    # while count < 101:
    # print(count)
    # count += 2
    #方法二:
    # count = 1
    # while count < 101:
    # if count % 2 == 1:
    # print(count)
    # count += 1

    # 5、求1-2+3-4+5 ... 99的所有数的和

    n = 1
    sum = 0
    while n < 100:
    if n % 2 == 0:
    n = -n
    sum = sum + n
    if n % 2 == 0:
    n = -n
    n += 1
    print('1-2+3-4+5 ... 99的所有数的和为%d'%sum)#相当于print(sum)

    # sum = 1
    # add = 0
    # while sum < 100:
    # if sum % 2 == 1:
    # add = add + sum
    # else:
    # add = add - sum
    # sum += 1
    # print(add)







  • 相关阅读:
    检测Linux硬盘IO数据
    获取OrangePI板子CPU温度
    ASP.Net开发WebAPI跨域访问(CORS)的精简流程
    一些常用复合命令
    关于Linux的虚拟内存管理
    Linux中组 与 用户的管理
    linux加载与使用ko驱动
    7z命令行 极限压缩指令
    nodejs的POST请求
    案例:用ajax 方法 解析xml
  • 原文地址:https://www.cnblogs.com/jassin-du/p/7696356.html
Copyright © 2011-2022 走看看