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  • Poj 2777 Count Color(线段树基础)

    又毁三观了.......虽然题目数据有坑:区间【a,b】可能会有a>b的情况,但是我一开始没有考虑它也能过。

    此外莫名其妙的TLE


    #include <iostream>
    #include <algorithm>
    #include <cmath>
    #include <cstdio>
    #include <cstdlib>
    #include <cstring>
    #include <string>
    #include <vector>
    #include <set>
    #include <map>
    #include <queue>
    #include <stack>
    #include <climits>
    #define MAX 100005
    #define INF 0x7FFFFFFF
    #define REP(i,s,t) for(int i=(s);i<=(t);++i)
    #define ll long long
    #define mem(a,b) memset(a,b,sizeof(a))
    #define mp(a,b) make_pair(a,b)
    #define L(x) x<<1
    #define R(x) x<<1|1
    # define eps 1e-5
    //#pragma comment(linker, "/STACK:36777216") ///传说中的外挂
    using namespace std;
    struct node {
        int left,right,mid,value,add;
    } edge[4*MAX];
    
    int aa[MAX];
    int vis[33];
    int ans ;
    void push_up(int x) {
        if(edge[R(x)].add != edge[L(x)].add)
            edge[x].add = 0;
    }
    
    void build(int l,int r,int num) {
    
        edge[num].left = l;
        edge[num].right = r;
        edge[num].mid = (l+r) >> 1;
        edge[num].add = 1;
        if(l == r) {
            edge[num].value = 1;
            return ;
        }
    
        build(l,edge[num].mid,num * 2); //左子树
        build(edge[num].mid + 1,r,num*2+1); //右子树
    
        push_up(num);
    
    }
    
    void push_down(int x) {
        if(edge[x].add) {
            //edge[L(x)].value = (edge[L(x)].right - edge[L(x)].left + 1 ) * edge[x].add ;
            //edge[R(x)].value = (edge[R(x)].right - edge[R(x)].left + 1) * edge[x].add ;
            edge[L(x)].add = edge[x].add ;
            edge[R(x)].add = edge[x].add ;
            edge[x].add = 0 ;
        }
    }
    void update(int l, int r, int k, int num) {
        if(edge[num].left >= l && edge[num].right <= r) {
            //当前区间包含于更新区间
            edge[num].add = k;
            return;
        }
        push_down(num);
        if(edge[num].mid < l) update(l, r, k, num*2+1);
        else if(edge[num].mid >= r) update(l, r, k, num*2);
        else {
            update(l, edge[num].mid, k, num*2);
            update(edge[num].mid + 1, r, k, num*2+1);
        }
        push_up(num);
    
    }
    
    void query(int l,int r,int num) {
        //if(l == edge[num].left && r == edge[num].right) //很想知道加了这个判断后TLE,不加400ms以内是为什么,按理加它是没有问题的......
            if(edge[num].add != 0) {
                if(vis[edge[num].add] == 0) {
                    ans++;
                    vis[edge[num].add] = 1;
                }
                return ;
            }
        push_down(num);
        if(r <= edge[num].mid)
            query(l,r,num*2);
        else if(l >= edge[num].mid + 1)
            query(l,r,num *2+1);
        else {
            query(l,edge[num].mid,num*2);
            query(edge[num].mid+1,r,num*2+1);
        }
    }
    
    int main() {
    
        int n,m,l,i,x,y,c;
        char str[3] ;
        cin >> n >> l >> m;
        build(1,n,1);
        for(i=1; i<=m; i++) {
            scanf("%s",str);
            if(str[0] == 'C') {
                scanf("%d%d%d",&x,&y,&c);
                if(x > y)
                    swap(x,y);
                update(x,y,c,1);
            }
            if(str[0] == 'P') {
                ans = 0;
                scanf("%d%d",&x,&y);
                if(x > y)
                    swap(x,y);
                mem(vis,0);
                query(x,y,1);
                printf("%d
    ",ans);
            }
    
        }
        return 0;
    }
    


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  • 原文地址:https://www.cnblogs.com/javawebsoa/p/3201215.html
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