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  • 237. Delete Node in a Linked List

    Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

    Given linked list -- head = [4,5,1,9], which looks like following:

        4 -> 5 -> 1 -> 9
    

    Example 1:

    Input: head = [4,5,1,9], node = 5
    Output: [4,1,9]
    Explanation: You are given the second node with value 5, the linked list
                 should become 4 -> 1 -> 9 after calling your function.
    

    Example 2:

    Input: head = [4,5,1,9], node = 1
    Output: [4,5,9]
    Explanation: You are given the third node with value 1, the linked list
                 should become 4 -> 5 -> 9 after calling your function.
    

    Note:

    • The linked list will have at least two elements.
    • All of the nodes' values will be unique.
    • The given node will not be the tail and it will always be a valid node of the linked list.
    • Do not return anything from your function.
    //Time: O(1), Space: O(1)
    //注意:这道题不需要遍历所以不需要知道head,条件node不是最后一个很重要,否则溢出
    class Solution {
        public void deleteNode(ListNode node) {
            if (node == null) {
                return;
            }
            
            node.val = node.next.val;
            node.next = node.next.next;
        }
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  • 原文地址:https://www.cnblogs.com/jessie2009/p/9772536.html
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