domino
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)
Problem Description
Little
White plays a game.There are n pieces of dominoes on the table in a
row. He can choose a domino which hasn't fall down for at most k times,
let it fall to the left or right. When a domino is toppled, it will
knock down the erect domino. On the assumption that all of the tiles are
fallen in the end, he can set the height of all dominoes, but he wants
to minimize the sum of all dominoes height. The height of every domino
is an integer and at least 1.
Input
The first line of input is an integer T ( 1≤T)
There are two lines of each test case.
The first line has two integer n and k, respectively domino number and the number of opportunities.( 2≤k,n≤100000)
The second line has n - 1 integers, the distance of adjacent domino d, 1≤d
There are two lines of each test case.
The first line has two integer n and k, respectively domino number and the number of opportunities.( 2≤k,n≤100000)
The second line has n - 1 integers, the distance of adjacent domino d, 1≤d
Output
For each testcase, output of a line, the smallest sum of all dominoes height
Sample Input
1
4 2
2 3 4
Sample Output
9
Source
思路:每次多推一次将最大的改成高度为1的骨牌;
坑点:k可能大于n;
#include<bits/stdc++.h> using namespace std; #define ll __int64 #define esp 0.00000000001 const int N=1e5+10,M=1e6+10,inf=1e9+10,mod=1000000007; int a[N]; int main() { int x,y,z,i,t; int T; scanf("%d",&T); while(T--) { scanf("%d%d",&x,&y); for(i=1;i<x;i++) scanf("%d",&a[i]); sort(a+1,a+x); ll ans=0; for(i=1;i<=(x-y);i++) ans+=a[i]+1; if(y<=x) ans+=y; else ans+=x; printf("%I64d ",ans); } return 0; }