zoukankan      html  css  js  c++  java
  • Codeforces Round #288 (Div. 2) C. Anya and Ghosts 模拟

    C. Anya and Ghosts
    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    Anya loves to watch horror movies. In the best traditions of horror, she will be visited by m ghosts tonight. Anya has lots of candles prepared for the visits, each candle can produce light for exactly t seconds. It takes the girl one second to light one candle. More formally, Anya can spend one second to light one candle, then this candle burns for exactly t seconds and then goes out and can no longer be used.

    For each of the m ghosts Anya knows the time at which it comes: the i-th visit will happen wi seconds after midnight, all wi's are distinct. Each visit lasts exactly one second.

    What is the minimum number of candles Anya should use so that during each visit, at least r candles are burning? Anya can start to light a candle at any time that is integer number of seconds from midnight, possibly, at the time before midnight. That means, she can start to light a candle integer number of seconds before midnight or integer number of seconds after a midnight, or in other words in any integer moment of time.

    Input

    The first line contains three integers mtr (1 ≤ m, t, r ≤ 300), representing the number of ghosts to visit Anya, the duration of a candle's burning and the minimum number of candles that should burn during each visit.

    The next line contains m space-separated numbers wi (1 ≤ i ≤ m1 ≤ wi ≤ 300), the i-th of them repesents at what second after the midnight the i-th ghost will come. All wi's are distinct, they follow in the strictly increasing order.

    Output

    If it is possible to make at least r candles burn during each visit, then print the minimum number of candles that Anya needs to light for that.

    If that is impossible, print  - 1.

    Examples
    input
    1 8 3
    10
    output
    3
    input
    2 10 1
    5 8
    output
    1
    input
    1 1 3
    10
    output
    -1
    Note

    Anya can start lighting a candle in the same second with ghost visit. But this candle isn't counted as burning at this visit.

    It takes exactly one second to light up a candle and only after that second this candle is considered burning; it means that if Anya starts lighting candle at moment x, candle is buring from second x + 1 to second x + t inclusively.

    In the first sample test three candles are enough. For example, Anya can start lighting them at the 3-rd, 5-th and 7-th seconds after the midnight.

    In the second sample test one candle is enough. For example, Anya can start lighting it one second before the midnight.

    In the third sample test the answer is  - 1, since during each second at most one candle can burn but Anya needs three candles to light up the room at the moment when the ghost comes.

    #include<bits/stdc++.h>
    using namespace std;
    #define ll long long
    #define pi (4*atan(1.0))
    #define eps 1e-14
    const int N=1e5+100,M=4e6+10,inf=1e9+10,mod=1e9+7;
    const ll INF=1e18+10;
    int a[N];
    int c[N];
    int main()
    {
        int m,t,r;
        scanf("%d%d%d",&m,&t,&r);
        for(int i=1;i<=m;i++)
            scanf("%d",&a[i]);
        if(t<r)return puts("-1");
        int flag=1;
        for(int i=r;i>=1;i--)
            c[flag++]=a[1]-i;
        int ans=r;
        for(int i=2;i<=m;i++)
        {
            int j;
            for(j=1;j<=r;j++)
            if(c[j]+t+1>a[i])break;
            flag=1;
            for(int k=j;k<=r;k++)
                c[flag++]=c[k];
            int p=r-j+1;
            p=r-p;
            if(p>0)
            {
                ans+=p;
                j=p;
                for(int k=0;k<j;k++)
                c[flag++]=a[i]-p,p--;
            }
        }
        printf("%d
    ",ans);
        return 0;
    }
  • 相关阅读:
    JavaScript中字符串处理的一些函数
    JavaScript中的call、apply、bind方法的区别
    JavaScript中的数组与伪数组的区别
    关于字符集和字符编码那些事
    JavaScript的技巧和最佳实践
    Linux下编辑利器vim,vimrc,viminfo的高级用法
    pdo,更高的sql安全性
    Centos下cacti的安装
    nginx中的502错误
    mac下webpagetest搭建
  • 原文地址:https://www.cnblogs.com/jhz033/p/5958093.html
Copyright © 2011-2022 走看看