Python 基础实战 -- 统计代码量

import os
import easygui as g

def StatisticeCodeLine(dir_name):
    file_dict = {".py":[0,0],".c":[0,0],".cpp":[0,0],".pas":[0,0],".asm":[0,0]}
    all_child_dir = os.walk(dir_name)
    
    for item in all_child_dir:
        for file in item[2]:
            file_name,file_extension = os.path.splitext(file)
            if file_extension in file_dict:
                file_dict[file_extension][0] += 1

            #------------------------------------------------------------
                with open(os.path.join(item[0],file),"r",encoding='utf-8') as f:
                    for i in f:
                        file_dict[file_extension][1] += 1
            #------------------------------------------------------------
                
            else:
                pass
       
    return file_dict


dir_name = g.diropenbox() #这里其实是一个获取需要递归的目录，在目录里找
file_dict = StatisticeCodeLine(dir_name)
total_line_count = 0
detail = ""
for key,value in file_dict.items():
    total_line_count += value[1]
    detail += str(key) + "源文件" + str(value[0]) + "个,源代码" + str(value[1])+"行
"

total_line_count = "您目前累积编写了{0}行代码，完成度{1}%
离10万行代码还差{2}行，请继续努力！".format(total_line_count,total_line_count / 1000,100000-total_line_count)

g.textbox(total_line_count,"统计结果",text=detail) #其实你想的话这里也可以用print替代