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  • 计算几何模板

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<cmath>
    #include<algorithm>
    
    #define eps 1e-7
    
    using namespace std;
    
    struct Point{
        double x,y;
        Point(){}
        Point(double x,double y):x(x),y(y){}
        void input()
        {
            scanf("%lf %lf",&x,&y);
        }
    };
    
    typedef Point Vector;//从程序上,Vector只是Point的别名
    
    
    int dcmp(double x)//控制精度
    {
        if(fabs(x)<eps) return 0;
        else return x<0?-1:1;
    }
    
    double toRad(double deg)//角度变为弧度
    {
        return deg/180.0*acos(-1.0);
    }
    
    Vector operator+(Vector A,Vector B)//向量加
    {
        return Vector(A.x+B.x, A.y+B.y);
    }
    
    Vector operator-(Vector A,Vector B)//向量减
    {
        return Vector(A.x-B.x,A.y-B.y);
    }
    
    Vector operator*(Vector A,double p)//向量数乘
    {
        return Vector(A.x*p,A.y*p);
    }
    
    Vector operator/(Vector A,double p)//向量数除
    {
        return Vector(A.x/p,A.y/p);
    }
    
    bool operator<(const Point &A,const Point &B)//两点比较
    {
        return dcmp(A.x-B.x)<0 || (dcmp(A.x-B.x) == 0 && dcmp(A.y-B.y) < 0);
    }
    
    bool operator==(const Point &A, const Point &B)//两点相等
    {
        return dcmp(A.x-B.x) == 0 && dcmp(A.y-B.y) == 0;
    }
    
    struct Line
    {
        Point s,e;
        Vector v;
        Line(){}
        Line(Point s, Point v, int type)://法向量式
           s(s),v(v){}
        Line(Point s, Point e):s(s),e(e)//两点式
        {
            v=e-s;
        }
    };
    
    
    double Dot(Vector A,Vector B)//向量点乘,|A|*|B|*cos<A,B>
    {
        return A.x*B.x+A.y*B.y;
    }
    
    double Length(Vector A)//向量模
    {
        return sqrt(Dot(A,A));
    }
    
    double Angle(Vector A,Vector B)//向量夹角
    {
        return acos(Dot(A,B)/Length(A)/Length(B));
    }
    
    double Cross(Vector A,Vector B)//向量叉积
    {
        return A.x*B.y-B.x*A.y;
    }
    
    double Area2(Point A,Point B,Point C)//向量的有向面积,三角形面积的2倍
    {
        return Cross(B-A,C-A);
    }
    
    double Dist(Point A,Point B)//两点之间的距离
    {
        return Length(A-B);
    }
    
    Vector Rotate(Vector A, double rad)//向量逆时针旋转
    {
        return Vector(A.x*cos(rad)-A.y*sin(rad), A.x*sin(rad)+A.y*cos(rad));
    }
    
    Vector Normal(Vector A)//向量单位法向量,前提不是零向量,即左转90度
    {
        double L=Length(A);
        return Vector(-A.y/L,A.x/L);
    }
    
    Point GetLineIntersection(Line l1,Line l2)//两直线的交点,调用前确保两条直线有唯一交点
    {
        Point P=l1.s;
        Vector v=l1.v;
        Point Q=l2.s;
        Vector w=l2.v;
        Vector u=P-Q;
        double t=Cross(w,u)/Cross(v,w);//注意分母不能为0
        return P+v*t;
    }
    
    double DistanceToLine(Point P,Line L)//点到直线的距离
    {
        Point A,B;
        A=L.s,B=L.e;
        Vector v1=B-A,v2=P-A;
        return fabs(Cross(v1,v2)/Length(v1));
    }
    
    double DistanceToSegment(Point P,Line L)//点到线段的距离
    {
        Point A,B;
        A=L.s,B=L.e;
        if(A==B) return Length(P-A);
        Vector v1=B-A,v2=P-A,v3=P-B;
        if(dcmp(Dot(v1,v2))<0) return Length(v2);
        else if(dcmp(Dot(v1,v3)>0)) return Length(v3);
        else return fabs(Cross(v1,v2))/Length(v1);
    }
    
    Point GetLineProjection(Point P,Line L)//点在直线上的投影
    {
        Point A,B;
        A=L.s,B=L.e;
        Vector v=B-A;
        return A+v*(Dot(v,P-A)/Dot(v,v));
    }
    
    bool OnSegment(Point p,Line l)//点在线段上包括端点
    {
        Point a1=l.s;
        Point a2=l.e;
        return dcmp(Cross(a1-p,a2-p))==0 && dcmp(Dist(p,a1)+Dist(p,a2)-Dist(a1,a2))==0;
    }
    
    bool Paralled(Line l1,Line l2)//直线平行
    {
        return dcmp(Cross(l1.e-l1.s,l2.e-l2.s))==0;
    }
    
    bool SegmentProperIntersection(Line l1,Line l2)//线段是否相交
    {
        if(Paralled(l1,l2))
            return false;
        Point t=GetLineIntersection(l1,l2);
        if(OnSegment(t,l1))
            return true;
        return false;
    }
    
    double PolygonArea(Point *p, int n)//求多边形面积
    {
        double area = 0;
        for(int i=1; i<n-1; i++)
          area += Cross(p[i]-p[0],p[i+1]-p[0]);
        return area/2.0;
    }
    
    int ConvexHull(Point *p,int n,Point *ch)    //求凸包
    {
        sort(p,p+n);
        int m=0;
        for ( int i = 0; i < n; ++i )
        {
            while ( m > 1 && Cross( ch[m - 1] - ch[m - 2], p[i] - ch[m - 2] ) <= 0 ) --m;
            ch[m++] = p[i];
        }
        int k = m;
        for ( int i = n - 2; i >= 0; --i )
        {
            while ( m > k && Cross( ch[m - 1] - ch[m - 2], p[i] - ch[m - 2] ) <= 0 ) --m;
            ch[m++] = p[i];
        }
        if ( n > 1 ) --m;
        return m;
    }
    
    
    int main()
    {
        
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/jiangjing/p/3917869.html
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