zoukankan      html  css  js  c++  java
  • 微积分学习笔记一:极限 导数 微分

    1、两个重要极限

    [lim_{x ightarrow0}frac{sinleft ( x ight )}{x}=1]

    [lim_{n ightarrow 0}left ( 1+frac{1}{n} ight )^{^{n}}=1]

    2、计算导数的方法:y=f(x)

    (1)求增量的增量: [Delta y=fleft ( x+Delta x ight )-fleft ( x ight )]

    (2) 计算比值:

    [frac{Delta y}{Delta x}=frac{fleft ( x+Delta x ight )-fleft(x ight )}{Delta x}]

    (3)求极限[lim_{Delta x ightarrow0}=frac{Delta y}{Delta x}]

    3、初等函数导数

    $left ( 1 ight )left (C ight )^{^{'}}=0$

    $left ( 2 ight )left (x^{a} ight )^{^{'}}=ax^{a-1}$

    $left ( 3 ight )left (log_{a}^{x} ight )^{^{'}}=frac{1}{xlna}left(a>0,a eq 0 ight )$

    $left ( 4 ight )left (ln x ight )^{^{'}}=frac{1}{x}$

    $left ( 5 ight )left (a^{x} ight )^{^{'}}=a^{x}ln x$

    $left ( 6 ight )left (e^{x} ight )^{^{'}}=e^{x}$

    $left ( 7 ight )left (sin x ight )^{^{'}}=cos x$

    $left ( 8 ight )left (cos x ight )^{^{'}}=-sin x$

    $left ( 9 ight )left (tan x ight )^{^{'}}=frac{1}{cos^{2}x}$

    $left ( 10 ight )left (frac{1}{tan x} ight )^{^{'}}=-frac{1}{sin^{2}x}$

    $left ( 11 ight )left (frac{1}{cos x} ight )^{^{'}}=frac{sin x}{cos^{2}x}$

    $left ( 12 ight )left (frac{1}{sin x} ight )^{^{'}}=-frac{cos x}{sin^{2}x}$

    $left ( 13 ight )left (arcsin x ight )^{^{'}}=frac{1}{sqrt{1-x^{2}}}left ( -1<x<1 ight )$

    $left ( 14 ight )left (arccos x ight )^{^{'}}=-frac{1}{sqrt{1-x^{2}}}left ( -1<x<1 ight )$

    $left ( 15 ight )left (arctan x ight )^{^{'}}=frac{1}{1+x^{2}}$

    $left ( 16 ight )left (arccot x ight )^{^{'}}=-frac{1}{1+x^{2}}left ( cot x=frac{1}{tan x} ight )$



    4、y=f(x)在x处导出存在且f'(x)!=0,当$left | Delta x ight |$很小时有

    [f left( x+ Delta x ight ) approx f left(x ight )+f^{^{'}}left(x ight )Delta x ]

  • 相关阅读:
    算法(第4版)-1.1.2 原始数据类型与表达式
    java值传递与引用传递实例
    (转载)理解Java中的引用传递和值传递
    (转载)深入Java关键字this的用法的总结
    如何判断数据库中是否存在某个表
    iforums之UEditor上传图片提示【未知错误】
    空指针和野指针
    self关键字
    自定义构造方法和description方法
    点语法
  • 原文地址:https://www.cnblogs.com/jianglangcaijin/p/6035903.html
Copyright © 2011-2022 走看看