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  • HDU 1240

     1 #include <iostream>
     2 #include <cstdio>
     3 using namespace std;
     4 
     5 const int MAX=13;
     6 
     7 char maze[MAX][MAX][MAX];
     8 
     9 struct {
    10     int i,j,k;
    11 }beg,des,que[1100],tmp,pushed;
    12 int f,l;
    13 char str[15],n;
    14 bool vis[MAX][MAX][MAX];
    15 int dir[6][3]={1,0,0,-1,0,0,0,1,0,0,-1,0,0,0,1,0,0,-1};
    16 
    17 bool ok(int i,int j,int k){
    18     if(i<0||i>=n||j<0||j>=n||k<0||k>=n||vis[i][j][k]||maze[i][j][k]=='X')
    19     return false;
    20     return true;
    21 }
    22 
    23 bool bfs(){
    24     int step=0; int ti,tj,tk;
    25     bool flag=false;
    26     while(f<l){
    27         int size=l-f;
    28         step++;
    29         while(size--){
    30             tmp=que[f++];
    31             if(tmp.i==des.i&&tmp.j==des.j&&tmp.k==des.k){
    32                 flag=true;
    33                 break;
    34             }
    35             for(int i=0;i<6;i++){
    36                 ti=tmp.i+dir[i][0];
    37                 tj=tmp.j+dir[i][1];
    38                 tk=tmp.k+dir[i][2];
    39                 if(ok(ti,tj,tk)){
    40                     vis[ti][tj][tk]=true;
    41                     pushed.i=ti; pushed.j=tj; pushed.k=tk;
    42                     que[l++]=pushed;
    43                 }
    44             }
    45         }
    46         if(flag) break;
    47     }
    48     if(flag){
    49         printf("%d %d
    ",n,step-1);
    50         return true;
    51     }
    52     return false;
    53 }
    54 
    55 
    56 int main(){
    57     while(scanf("%s %d",str,&n)!=EOF){
    58         for(int i=0;i<n;i++){
    59             for(int j=0;j<n;j++)
    60             cin>>maze[i][j];
    61         }
    62     //    cout<<"NO"<<endl;
    63         scanf("%d%d%d",&beg.j,&beg.k,&beg.i);
    64         scanf("%d%d%d",&des.j,&des.k,&des.i);
    65         cin>>str;
    66     //    cout<<"YES"<<endl;
    67         memset(vis,false,sizeof(vis));
    68         f=l=0;
    69         if(beg.i==des.i&&beg.j==des.j&&beg.k==des.k){
    70             printf("%d 0
    ",n);
    71             continue;
    72         }
    73         vis[beg.i][beg.j][beg.k]=true;
    74         que[l++]=beg;
    75         if(!bfs())
    76         printf("NO ROUTE
    ");
    77     }
    78     return 0;
    79 }
    View Code
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  • 原文地址:https://www.cnblogs.com/jie-dcai/p/3795593.html
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