zoukankan      html  css  js  c++  java
  • java 核心技术卷一笔记 6 .1接口 lambda 表达式 内部类

    6.1 接口不是类,是对类的一组需求的描述,这些类需要遵守接口描述的统一格式进行定义。例如:Arrays类中sort方法(可以对对象数组进行排序)前提是对象所属的类必须实现了Comparable 接口。

    public interface Comparable
    {
        int compareTo(Object other)
    }
    Comparable
    public interface Comparable<T>
    {
        int compareTo(T other)
    }
    Comparable泛型

    接口的方法自动的属于public;接口中可以定义多个方法;可以定义常量;接口不能含有实例域;

    实现接口:1)将类声明为实现给定的接口(implements);2)对接口中的所有方法进行定义。

    comparaTo 方法实现

    1 public int ComparaTo(Object otherObject)
    2 {
    3     Employee other (Employee) otherObject;
    4     return Double.compare(salary, other.salary);
    5 }
    静态Double.compare方法(第一个参数<第二个参数,返回一个负数,二者相等,返回0,
    comparaTo 方法 泛型实现
    1 class Employee implements Comparable<Employee>{
    2 public int ComparaTo(Employee other)
    3 {
    4     return Double.compare(salary, other.salary);
    5 }
    }

        注意 Object 参数进行类型转换 

    为什么不在Employee类直接提供一个comparableTo方法呢?主要原因在于java是一种强类型(strongly typed)语言。在调用方法时编译器会检查这个方法是否存在。

     1 package cc.openhome;
     2 import java.util.Arrays;
     3 public class JieKou {
     4     public static void main(String[] args) {
     5         // TODO code application logic here
     6         Employee[] staff =new Employee[3];
     7         staff[0] =new Employee("harry Hacker", 75000);
     8         staff[1]=new Employee("Carl Cracker", 355000);
     9         staff[2]=new Employee("Tony Tester", 228000);
    10         Arrays.sort(staff);
    11         for(Employee e:staff)
    12             System.out.println("name="+e.getName()+",salarry="+e.getSalary());
    13     } 
    14 }
    15 class Employee  implements Comparable<Employee>
    16 {
    17     private String name;
    18     private double salary;
    19     public Employee(String name,double salary)
    20     {
    21         this.name =name;
    22         this.salary=salary;
    23     }
    24     public String getName()
    25     {
    26         return name ;
    27     }
    28     public double getSalary()
    29     {
    30         return salary;
    31     }
    32     public void raiseSalary(double byPercent)
    33     {
    34         double raise =salary*byPercent/100;
    35         salary +=raise;
    36     }
    37     public int compareTo(Employee other)
    38     {
    39         return Double.compare(salary,other.salary);
    40     }  
    41 }
    name=harry Hacker,salarry=75000.0
    name=Tony Tester,salarry=228000.0
    name=Carl Cracker,salarry=355000.0
    成功构建 (总时间: 0 秒)
    run:





  • 相关阅读:
    37.leetcode11_container_with_most_water
    36.leetcode8_string_to_integer
    34.leetcode15&5_time_limit_exceeded
    35.leetcode15_3Sum
    33.leetcode6_zigzag_conversion
    32.leetcode3_longest_substring_without_repeating_characters
    31.leetcode2_add_two_numbers
    29.leetcode172_factorial_trailing_zeroes
    30.leetcode171_excel_sheet_column_number
    [LeetCode] 43.Multiply Strings 字符串相乘
  • 原文地址:https://www.cnblogs.com/jinmoon/p/8579320.html
Copyright © 2011-2022 走看看