C++ | char* 在类中实践笔记

　　在C++中，当类中定义有char * 变量时，在传参，构造函数，复制构造函数如何创建及赋值，来一个简单的例子就明了：

#include<iostream>
#include<string>
#pragma warning(disable: 4996)
using namespace std;

class Goods {
public:
    Goods();
    Goods(const char* _name, int _id);
    Goods(const Goods& goods);
    void Printf();
    //省略....
private:
    char *name;
    int id;
};

Goods::Goods(){}
Goods::Goods(const char* _name, int _id) :name(new char[strlen(_name) + 1]), id(_id) {
    strcpy(name, _name);
}
Goods::Goods(const Goods& goods) : name(new char[strlen(goods.name) + 1]), id(goods.id) {
    strcpy(name,goods.name);
}
void Goods::Printf() {
    cout << this->id << "  " << this->name << endl;
}
int main() {
    Goods goods("雪碧",1);
    goods.Printf();
    system("pause");
}