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  • [hdu3631]背包或中途相遇法

    暴力的背包:

     1 #pragma comment(linker, "/STACK:10240000,10240000")
     2 
     3 #include <iostream>
     4 #include <cstdio>
     5 #include <algorithm>
     6 #include <cstdlib>
     7 #include <cstring>
     8 #include <map>
     9 #include <queue>
    10 #include <deque>
    11 #include <cmath>
    12 #include <vector>
    13 #include <ctime>
    14 #include <cctype>
    15 #include <set>
    16 
    17 using namespace std;
    18 
    19 #define mem0(a) memset(a, 0, sizeof(a))
    20 #define lson l, m, rt << 1
    21 #define rson m + 1, r, rt << 1 | 1
    22 #define define_m int m = (l + r) >> 1
    23 #define rep(a, b) for(int a = 0; a < b; a++)
    24 #define all(a) (a).begin(), (a).end()
    25 #define lowbit(x) ((x) & (-(x)))
    26 #define constructInt4(name, a, b, c, d) name(int a = 0, int b = 0, int c = 0, int d = 0): a(a), b(b), c(c), d(d) {}
    27 #define constructInt3(name, a, b, c) name(int a = 0, int b = 0, int c = 0): a(a), b(b), c(c) {}
    28 #define constructInt2(name, a, b) name(int a = 0, int b = 0): a(a), b(b) {}
    29 #define pc(a) putchar(a)
    30 #define ps(a) printf("%s", a)
    31 #define pd(a) printf("%d", a)
    32 #define sd(a) scanf("%d", &a)
    33 
    34 typedef double db;
    35 typedef long long LL;
    36 typedef pair<int, int> pii;
    37 typedef multiset<int> msi;
    38 typedef set<int> si;
    39 typedef vector<int> vi;
    40 typedef map<int, int> mii;
    41 
    42 const int dx[8] = {0, 1, 0, -1, 1, 1, -1, -1};
    43 const int dy[8] = {1, 0, -1, 0, -1, 1, 1, -1};
    44 const int maxn = 1e5 + 7;
    45 const int maxm = 1e5 + 7;
    46 const int maxv = 1e7 + 7;
    47 const int max_val = 1e6 + 7;
    48 const int MD = 1e9 +7;
    49 const int INF = 1e9 + 7;
    50 const double PI = acos(-1.0);
    51 const double eps = 1e-10;
    52 
    53 template<class T> T gcd(T a, T b) { return b == 0? a : gcd(b, a % b); }
    54 
    55 int t, sum[33], a[33];
    56 bool f[10000007];
    57 int main() {
    58     //freopen("in.txt", "r", stdin);
    59     int n;
    60     while (cin >> n >> t) {
    61         rep(i, n) sd(a[i]);
    62         sort(a, a + n);
    63         sum[0] = a[0];
    64         rep(i, n - 1) sum[i + 1] = sum[i] + a[i + 1];
    65         mem0(f);
    66         f[0] = true;
    67         rep(i, n) {
    68             int maxt = min(t, sum[i]);
    69             for (int j = maxt; j >= a[i]; j--) {
    70                 f[j] = f[j] || f[j - a[i]];
    71             }
    72         }
    73         int ans;
    74         for (int i = t; i >= 0; i--) {
    75             if (f[i]) {
    76                 ans = i;
    77                 break;
    78             }
    79         }
    80         cout << ans << endl;
    81     }
    82     return 0;
    83 }
    View Code
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  • 原文地址:https://www.cnblogs.com/jklongint/p/4419005.html
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