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  • [hdu4670 Cube number on a tree]点分治

    题意:给一个N个带权节点的树,权值以给定的K个素数为因子,求路径上节点乘积为立方数的路径条数

    思路:立方数的性质是每个因子的个数为3的倍数,那么每个因子只需要保存0-2三个状态即可,然后路径就可以转化为一个K位3进制数,点分治后,便可以用一个map来查询路径经过根的答案。代码与上一题(poj1741)类似:http://www.cnblogs.com/jklongint/p/4960052.html

    #pragma comment(linker,"/STACK:10240000,10240000")
    #include <iostream>
    #include <algorithm>
    #include <cstdio>
    #include <cstring>
    #include <ctime>
    #include <map>
    #include <vector>
    using namespace std;
    #define X first
    #define Y second
    #define pb(x) push_back(x)
    #define mp(x, y) make_pair(x, y)
    #define all(a) (a).begin(), (a).end()
    #define mset(a, x) memset(a, x, sizeof(a))
    #define mcpy(a, b) memcpy(a, b, sizeof(b))
    #define cas() int T, cas = 0; cin >> T; while (T --)
    template<typename T>bool umax(T&a, const T&b){return a<b?(a=b,true):false;}
    template<typename T>bool umin(T&a, const T&b){return b<a?(a=b,true):false;}
    typedef long long ll;
    typedef pair<int, int> pii;
    
    #ifndef ONLINE_JUDGE
        #include "local.h"
    #endif
    
    const int N = 5e4 + 7;
    const int M = N;
    const int inf = 1e9 + 7;
    
    namespace Edge {
        int last[N], to[M << 1], next[M << 1], cntE;
        void init() {
            cntE = 0;
            memset(last, -1, sizeof(last));
        }
        void addEdge(int u, int v) {
            to[cntE] = v;
            next[cntE] = last[u];
            last[u] = cntE ++;
        }
    }
    
    int n, K;
    
    struct Node {
        char p[33];
        char &operator[] (int x) {
            return p[x];
        }
        ll getNum() {
            ll ans = 0;
            for (int i = 0; i < K; i ++) {
                ans = ans * 3 + p[i];
            }
            return ans;
        }
        ll getComplement() {
            ll ans = 0;
            for (int i = 0; i < K; i ++) {
                ans = ans * 3 + (p[i]? 3 - p[i] : 0);
            }
            return ans;
        }
        Node operator+ (Node &that) {
            Node ans;
            for (int i = 0; i < K; i ++) {
                ans[i] = p[i] + that[i];
                if (ans[i] >= 3) ans[i] -= 3;
            }
            return ans;
        }
        Node operator- (Node &that) {
            Node ans;
            for (int i = 0; i < K; i ++) {
                ans[i] = p[i] - that[i];
                if (ans[i] < 0) ans[i] += 3;
            }
            return ans;
        }
    };
    
    namespace Center {
        int root, siz, son[N];
        void init() {
            siz = inf;
        }
        void getRoot(int cur, int fa, int total, bool used[]) {
            son[cur] = 0;
            int buf = 0;
            for (int i = Edge::last[cur]; ~i; i = Edge::next[i]) {
                int to = Edge::to[i];
                if (to != fa && !used[to]) {
                    getRoot(to, cur, total, used);
                    son[cur] += son[to] + 1;
                    buf = max(buf, son[to] + 1);
                }
            }
            buf = max(buf, total - son[cur] - 1);
            if (buf < siz || buf == siz && cur < siz) {
                siz = buf;
                root = cur;
            }
        }
    }
    
    bool used[N];
    Node r[N];
    
    void getNode(int cur, int fa, Node sum, vector<Node> &vt, bool used[]) {
        vt.pb(sum);
        for (int i = Edge::last[cur]; ~i; i = Edge::next[i]) {
            int to = Edge::to[i];
            if (to != fa && !used[to]) getNode(to, cur, sum + r[to], vt, used);
        }
    }
    
    ll getAns(vector<Node> &vt, Node &s) {
        ll ans = 0;
        map<ll, int> mp;
        for (int i = 0; i < vt.size(); i ++) {
            mp[vt[i].getNum()] ++;
            ans += mp[(vt[i] - s).getComplement()];
        }
        return ans;
    }
    
    ll work(int cur) {
        used[cur] = true;
        vector<Node> total;
        total.push_back(r[cur]);
        ll ans = 0;
        for (int i = Edge::last[cur]; ~i; i = Edge::next[i]) {
            int to = Edge::to[i];
            if (!used[to]) {
                vector<Node> local;
                getNode(to, cur, r[cur] + r[to], local, used);
                ans -= getAns(local, r[cur]);
                for (int j = 0; j < local.size(); j ++) {
                    total.push_back(local[j]);
                }
                Center::init();
                Center::getRoot(to, cur, local.size(), used);
                ans += work(Center::root);
            }
        }
        return ans += getAns(total, r[cur]);
    }
    
    ll p[N], a[N];
    
    int main() {
    #ifndef ONLINE_JUDGE
        freopen("in.txt", "r", stdin);
        //freopen("out.txt", "w", stdout);
    #endif // ONLINE_JUDGE
        while (cin >> n >> K) {
            Edge::init();
            Center::init();
            mset(r, 0);
            mset(used, 0);
            for (int i = 0; i < K; i ++) {
                scanf("%I64d", p + i);
            }
            for (int i = 1; i <= n; i ++) {
                scanf("%I64d", a + i);
                for (int j = 0; j < K; j ++) {
                    ll cur = p[j];
                    while (a[i] % cur == 0) {
                        r[i][j] ++;
                        if (r[i][j] == 3) r[i][j] = 0;
                        cur *= p[j];
                    }
                }
            }
            int u, v;
            for (int i = 1; i < n; i ++) {
                scanf("%d%d", &u, &v);
                Edge::addEdge(u, v);
                Edge::addEdge(v, u);
            }
            Center::getRoot(1, 0, n, used);
            cout << work(Center::root) << endl;
        }
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/jklongint/p/4960231.html
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