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  • js 获取url 参数

        function getUrlArg(url,key){
            var arr = url.split('?');
            var argStr = arr.length >1 ? arr[1]:"";
            if(!argStr){
                return "";
            }
            var arr2 = argStr.split('&').map(item=>item.split('='));
            var res = arr2.find(item=>item[0] == key);
            if(res){
                return res.length > 1 ? res[1] :"";
            }else{
                return "";
            }
        }
        var url = "https://www.xxx.com/s?name=zhang&age=12&aa";
        console.log(getUrlArg(url,"name"));
        console.log(getUrlArg(url,"age"));
        console.log(getUrlArg(url,"sex"));
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  • 原文地址:https://www.cnblogs.com/jlyuan/p/12031802.html
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