package LeetCode_261 import java.util.* /** * 261. Graph Valid Tree * Lock by leetcode * https://www.lintcode.com/problem/graph-valid-tree/description * * Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), * write a function to check whether these edges make up a valid tree. You can assume that no duplicate edges will appear in edges. Since all edges are undirected, [0, 1] is the same as [1, 0] and thus will not appear together in edges. * */ class Solution { /* * valid Tree, must a connected graph and acyclic * */ fun validTree(n: Int, edges: Array<IntArray>): Boolean { val graph = HashMap<Int, ArrayList<Int>>() //init for (i in 0 until n) { graph[i] = ArrayList() } //create graph for (edge in edges) { graph[edge.get(0)]!!.add(edge.get(1)) graph[edge.get(1)]!!.add(edge.get(0)) } val visited = BooleanArray(n) val queue = LinkedList<Int>() queue.offer(0) while (!queue.isEmpty()) { val top = queue.poll() if (visited[top]) { return false } visited[top] = true val list = graph[top] if (list == null) { continue } for (item in list) { if (!visited[item]) { queue.offer(item) } } } for (v in visited) { if (!v) { return false } } return true } }