zoukankan      html  css  js  c++  java
  • 582. Kill Process

    package LeetCode_582
    
    import java.util.*
    import kotlin.collections.ArrayList
    import kotlin.collections.HashMap
    
    /**
     * 582.Kill Process
     * (Prime)
     *Given n processes, each process has a unique PID (process id) and its PPID (parent process id).
    Each process only has one parent process, but may have one or more children processes.
    This is just like a tree structure. Only one process has PPID that is 0, which means this process has no parent process.
    All the PIDs will be distinct positive integers.
    We use two list of integers to represent a list of processes,
    where the first list contains PID for each process and the second list contains the corresponding PPID.
    Now given the two lists, and a PID representing a process you want to kill, return a list of PIDs of processes that will be killed in the end.
    You should assume that when a process is killed, all its children processes will be killed. No order is required for the final answer.
    
    Example 1:
    Input:
    pid =  [1, 3, 10, 5]
    ppid = [3, 0, 5, 3]
    kill = 5
    Output: [5,10]
    Explanation:
        3
      /  
     1    5
         /
        10
    Kill 5 will also kill 10.
    
    Note:
    1. The given kill id is guaranteed to be one of the given PIDs.
    2. n >= 1.
     * */
    class Solution {
        /*
        * Solution: BFS + HashMap, hashmap to create relation of pid and ppid,
        * for example:
        * pid =  [1, 3, 10, 5] , ppid = [3, 0, 5, 3], map is: {0=[3], 3=[1, 5], 5=[10]};
        * Time complexity:O(n), Space complexity:O(n)
        * */
        fun killProcess(pid:IntArray, ppid:IntArray, kill:Int): List<Int>{
            val result = ArrayList<Int>()
            //key is ppid, value is list of children
            val map = HashMap<Int,ArrayList<Int>>()
            for (i in pid.indices){
                val ppidValue = ppid[i]
                if (!map.containsKey(ppidValue)){
                    map.put(ppidValue,ArrayList())
                }
                map.get(ppidValue)?.add(pid[i])
            }
    
            val queue = LinkedList<Int>()
            //put the ppid would like to kill
            queue.offer(kill)
            while (queue.isNotEmpty()){
                val p = queue.poll()
                result.add(p)
                //get it children list
                val list = map.get(p)
                if (list != null){
                    for (item in list){
                        queue.offer(item)
                    }
                }
            }
    
            return result
        }
    }
  • 相关阅读:
    mysql事件之修改事件(ALTER EVENT)&禁用事件(DISABLE)&启用事件(ENABLE)&事件重命名&数据库事件迁移
    用Sqoop进行Hive和MySQL之间的数据互导
    Sqoop使用手册
    azkaban使用案例
    azkaban3.x安装
    工作流调度器azkaban概述
    将 Hive 空值统一为 N
    [模拟] [洛谷] P1765 手机
    [NYISTOJ] 题目845 无主之地1
    [NYISTOJ] 题目 458 小光棍数
  • 原文地址:https://www.cnblogs.com/johnnyzhao/p/13467154.html
Copyright © 2011-2022 走看看