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  • zookeeper 异常 :stat is not executed because it is not in the whitelist. Connection closed b

    1 .问题 

      1.启动 zookeeper 后 用指令:  telnet 127.0.0.1 2181 连接 提示输入指令 :stat 后报错,然后关闭连接

        

    2.问题解决:

      修改启动指令 zkServer.sh ,往里面添加 :ZOOMAIN="-Dzookeeper.4lw.commands.whitelist=* ${ZOOMAIN}"

      步骤 :

        1.cd  apache-zookeeper-3.5.5-bin 

        2. vim vim  bin/zkServer.sh

        3.修改 ,添加:ZOOMAIN="-Dzookeeper.4lw.commands.whitelist=* ${ZOOMAIN}" ,保存退出

        

          JMXLOG4J=true
        fi
        echo "ZooKeeper remote JMX Port set to $JMXPORT" >&2
        echo "ZooKeeper remote JMX authenticate set to $JMXAUTH" >&2
        echo "ZooKeeper remote JMX ssl set to $JMXSSL" >&2
        echo "ZooKeeper remote JMX log4j set to $JMXLOG4J" >&2
        ZOOMAIN="-Dcom.sun.management.jmxremote -Dcom.sun.management.jmxremote.port=$JMXPORT -Dcom.sun.management.jmxremote.authenticate=$JMXAUTH -Dcom.sun.management.jmxremote.ssl=$JMXSSL -Dzookeeper.jmx.log4j.disable=$JMXLOG4J org.apache.zookeeper.server.quorum.QuorumPeerMain"
      fi
    else
        echo "JMX disabled by user request" >&2
        ZOOMAIN="org.apache.zookeeper.server.quorum.QuorumPeerMain"
    fi
    ZOOMAIN="-Dzookeeper.4lw.commands.whitelist=* ${ZOOMAIN}"
    if [ "x$SERVER_JVMFLAGS" != "x" ]
    then
        JVMFLAGS="$SERVER_JVMFLAGS $JVMFLAGS"
    fi
    
    if [ "x$2" != "x" ]
    then
        ZOOCFG="$ZOOCFGDIR/$2"
    fi

      4.重启: bin/zkServer.sh start

    参考文章 :https://blog.csdn.net/x763795151/article/details/80599498

          

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  • 原文地址:https://www.cnblogs.com/jonrain0625/p/11377508.html
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