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  • 螺旋输出N*N矩阵

     1 #include <iostream>
     2 #include <vector>
     3 using namespace std;
     4 int main() {
     5     int x[] = { 0, 1, 0, -1 };
     6     int y[] = { 1, 0, -1, 0 };
     7     int n;
     8     int pos_x = 0;
     9     int pos_y = 0;
    10     cin >> n;
    11     int counter = 1;
    12     vector<vector<int> > A(n, vector<int>(n, 0));
    13     int i;
    14     for (i = n - 1; i > 0; i -= 2) {
    15         for (int k = 0; k < 4; k++) {
    16             for (int j = 0; j < i; j++) {
    17                 A[pos_x][pos_y] = counter;
    18                 counter++;
    19                 pos_x += x[k];
    20                 pos_y += y[k];
    21             }
    22         }
    23         pos_x++;
    24         pos_y++;
    25     }
    26     if (i == 0)
    27         A[pos_x][pos_y] = counter;
    28     for (int i = 0; i < n; i++) {
    29         for (int j = 0; j < n; j++) {
    30             cout << A[i][j] << "  ";
    31         }
    32         cout << endl;
    33     }
    34     return 0;
    35 }
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  • 原文地址:https://www.cnblogs.com/kakamilan/p/2695997.html
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