基础语句
select * from tb1;
select * from tb1 limit 3;
select name,age from tb1;
select name,age from tb1 where age = 25;
select * from tb1 where age != 28;
select * from tb1 where age >= 25 and age <=28;
select name,age from tb1 where age between 25 and 28;
select * from tb1 where age = 25 or age = 28;
select * from tb1 where age not between 25 and 28;
select * from tb1 where age < 25 or age > 28;
select * from tb1 where name like 'j%';
select * from tb1 where name like 't__';
select * from tb1 where name rlike '^t.*';
select * from tb1 where age in (22,23,24,25);
select * from tb1 where age not in (28,33,43);
select * from tb1 order by age;
select * from tb1 order by age asc;
select * from tb1 order by age desc;
select * from tb1 order by age desc,name asc;
select distinct age from students; #去重查询
select name as StuName,age from tb1;
分组与聚合
select gender,sum(age) from students group by gender;
select classid,avg(age) as avgage from students group by classid having avgage > 25;
select sum(age) from students where age > 19 group by gender;
# 交叉连接
select * from t1 cross join t2 cross join t3;
select * from t1,t2,t3;
# 内连接
select * from t1 inner join t2 on t1.t1id=t2.t2id;
select * from t1,t2 where t1.t1id=t2.t2id;
# 外连接
select * from t1 right outer join t2 on t1id=t2id;
select * from t1 left outer join t2 on t1id=t2id;
select * from t1 right join t2 on t1id=t2id;
select * from t1 left join t2 on t1id=t2id;
#联合查询
select * from t1 union select * from t2; #重复数据合并
select * from t2 union all select * from t4; #显示重复记录
#全连接
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