@ExceptionHandler() 如果异常被try-catch就不会被接收, 抛出的checked exception 能被接收
@RestController
public class TestController2 {
@RequestMapping("/test5")
public String test5() {
try {
throw new RuntimeException();
} catch (RuntimeException e) {
System.out.println("异常被捕获");
e.printStackTrace();
}
return "hello world";
}
@RequestMapping("/test6")
public void test6() throws IOException {
System.out.println("controller IOException throws");
throw new IOException();
}
@RequestMapping("/test7")
public void test7() {
try {
throw new IOException();
} catch (IOException e) {
System.out.println("controller IOException try-catch");
e.printStackTrace();
}
}
/*
@ExceptionHandler 能接收抛出的checked exception,但是如果异常被try-catch就不能被接收
*/
@ExceptionHandler(IOException.class)
public void catchIoException() {
System.out.println("handler IOException");
}
/*
如果unchecked exception 被try-catch了就不能被@ExceptionHandler接收
*/
@ExceptionHandler(RuntimeException.class)
public void catchRuntimeException() {
System.out.println("handler RuntimeException");
}
}
可以通过如下方法处理异常
@ExceptionHandler(AuthorizationException.class)
private ModelAndView handleAuthorizationException(AuthorizationException e) {
HashMap<String, Object> map = new HashMap<>();
map.put("msg", "你没有权限这么做");
//如果要自定义传属性到getAttributes()中必须通过这种方法,不能通过@RequestStatus
map.put("javax.servlet.error.status_code", HttpStatus.BAD_REQUEST.value());
return new ModelAndView("forward:/error", map);
}