【C/C++】拔河比赛/分组/招商银行

题目：小Z组织训练营同学进行一次拔河比赛，要从n（2≤n≤60,000）个同学中选出两组同学参加（两组人数可能不同）。对每组同学而言，如果人数超过1人，那么要求该组内的任意两个同学的体重之差的绝对值不超过k（包含k）。问最多有几个同学能参加比赛？
我的超时了

#include <bits/stdc++.h>
using namespace std;
const int maxn = 60010;
int data[maxn] = {0};

int main()
{
    int n, k;
    scanf("%d %d", &n, &k);
    for(int i = 0; i < n; i++)
    {
        scanf("%d", &data[i]);
    }
    sort(data, data + n);
    int flag = 0;
    // 0~flag-1 flag~n-1
    int maxxxx = 0;
    for (int flag = 1; flag <= n - 1; flag++)
    {
        int i = 0; int j = 0;
        int res1 = 0; int maxn1 = 1;
        for (i = 0; i < flag; i++)
        {
            for (j = i; j < flag; j++)
            {
                if ( data[j] - data[i] <= k ) 
                {
                    res1 = j - i + 1;
                    maxn1 = max(maxn1, res1);
                }
                if ( data[j] - data[i] > k)
                {
                    break;
                }
            }
        }
        int res2 = 0; int maxn2 = 1;
        for (i = flag; i <= n - 1; i++)
        {
            for (j = i; j <= n - 1; j++)
            {
                if ( data[j] - data[i] <= k )
                {
                    res2 = j - i + 1;
                    maxn2 = max(maxn2, res2);
                }
                if ( data[j] - data[i] > k)
                {
                    break;
                }
            }
        }
        // cout << maxn1 << " " << maxn2 << endl;
        maxxxx = max(maxxxx, (maxn1 + maxn2));
    }
    cout << maxxxx << endl;
    system("pause");
}

看通过了的大佬是这样写的

#include<iostream>
#include<stdio.h>
#include<math.h>
#include<string>
#include<string.h>
#include<algorithm>
using namespace std;
#define ll long long 
const int maxn = 1e5+10;
const ll mod = 100000007;
int n;
ll a[maxn];
ll k;
ll Max[maxn];
ll ans;
ll mMax[maxn];
void wk(int x)
{
	int mid,bns=x,lb=x,ub=n;
	while(ub>=lb)
	{
		mid=(lb+ub)/2;
		if(a[mid]-a[x]<=k)
		{
			bns=mid; lb=mid+1;
		}
		else ub=mid-1;
	}
	Max[x]=bns;
}
int main()
{
	scanf("%d%lld",&n,&k);
	for(int i=1;i<=n;i++) scanf("%lld",&a[i]);
	sort(a+1,a+1+n);
	for(int i=1;i<=n;i++) wk(i);
	for(int i=n;i;i--) mMax[i]=max(mMax[i+1],Max[i]-i+1);
	for(int i=1;i<=n;i++)
	{
		ans=max(ans,(Max[i]-i+1) + mMax[(int)Max[i]+1]);
	}
	printf("%lld",ans);
	return 0;
}