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  • [HDOJ5900]QSC and Master(区间dp)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5900

    巧妙的地方在于第四个转移,假如dp(i,j)区间内所有的都取了,那状态的值应该是s(j)-s(i-1)

     1 #include <bits/stdc++.h>
     2 using namespace std;
     3 #define fr first
     4 #define sc second
     5 #define cl clear
     6 #define BUG puts("here!!!")
     7 #define W(a) while(a--)
     8 #define pb(a) push_back(a)
     9 #define Rint(a) scanf("%d", &a)
    10 #define Rll(a) scanf("%I64d", &a)
    11 #define Rs(a) scanf("%s", a)
    12 #define Cin(a) cin >> a
    13 #define FRead() freopen("in", "r", stdin)
    14 #define FWrite() freopen("out", "w", stdout)
    15 #define Rep(i, len) for(int i = 0; i < (len); i++)
    16 #define For(i, a, len) for(int i = (a); i < (len); i++)
    17 #define Cls(a) memset((a), 0, sizeof(a))
    18 #define Clr(a, x) memset((a), (x), sizeof(a))
    19 #define Full(a) memset((a), 0x7f7f7f, sizeof(a))
    20 #define lrt rt << 1
    21 #define rrt rt << 1 | 1
    22 #define pi 3.14159265359
    23 #define RT return
    24 #define lowbit(x) x & (-x)
    25 #define onecnt(x) __builtin_popcount(x)
    26 typedef long long LL;
    27 typedef long double LD;
    28 typedef unsigned long long ULL;
    29 typedef pair<int, int> pii;
    30 typedef pair<string, int> psi;
    31 typedef pair<LL, LL> pll;
    32 typedef map<string, int> msi;
    33 typedef vector<int> vi;
    34 typedef vector<LL> vl;
    35 typedef vector<vl> vvl;
    36 typedef vector<bool> vb;
    37 
    38 const int maxn = 330;
    39 int n;
    40 pii a[maxn];
    41 LL s[maxn];
    42 LL dp[maxn][maxn];
    43 
    44 signed main() {
    45   //FRead();
    46   int T;
    47   Rint(T);
    48   W(T) {
    49     Cls(s);
    50     Rint(n);
    51     For(i, 1, n+1) Rint(a[i].first);
    52     For(i, 1, n+1) {
    53       Rint(a[i].second);
    54       s[i] = s[i-1] + a[i].second;
    55     }
    56     Cls(dp);
    57     For(k, 2, n+1) {
    58       For(i, 1, n-k+2) {
    59         int j = i + k - 1;
    60         For(p, i, j) dp[i][j] = max(dp[i][j], dp[i][p]+dp[p+1][j]);
    61         if(__gcd(a[i].first, a[j].first) > 1) {
    62           if(k == 2) dp[i][j] = a[i].second + a[j].second;
    63           else {
    64             if(s[j-1] - s[i] == dp[i+1][j-1]) {
    65               dp[i][j] = max(dp[i][j], dp[i+1][j-1]+a[i].second+a[j].second);
    66             }
    67           }
    68           dp[i][j] = max(dp[i][j], max(dp[i][j-1], dp[i+1][j]));
    69         }
    70       }
    71     }
    72     printf("%I64d
    ", dp[1][n]);
    73   }
    74   RT 0;
    75 }
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  • 原文地址:https://www.cnblogs.com/kirai/p/5885906.html
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