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  • java递归查找最后一条记录

    public List<Operator> sx(List<Operator> list) {
    List<Operator> sxList = new ArrayList<Operator>();
    for (int i = 0; i < list.size(); i++) {
    long time = System.currentTimeMillis();
    if (time > Long.parseLong(list.get(i).getAutoTransferTime())
    && time < Long.parseLong(list.get(i).getAutoTransterEndTime())) {


    Map<String, Object> map2 = new HashMap<String, Object>();
    map2.put("autoTransferService", list.get(i).getAutoTransferService());
    List<Operator> transferList1 = operatorService.selectTransferByTelphone(map2);
    if (transferList1 == null || transferList1.isEmpty()) {
    System.err.println("没有找到此客服!");
    } else {
    list.remove(i);
    sxList.add(transferList1.get(0));
    }
    } else {
    sxList.add(list.get(i));
    }
    }
    for (Operator sxLists : sxList) {
    long time = System.currentTimeMillis();
    if (time > Long.parseLong(sxLists.getAutoTransferTime())
    && time < Long.parseLong(sxLists.getAutoTransterEndTime())) {
    sx(sxList);
    }
    }
    return sxList;
    }

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  • 原文地址:https://www.cnblogs.com/cw828/p/10470264.html
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