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  • poj 1007 DNA sorting (qsort)

    DNA Sorting
    Time Limit: 1000MS   Memory Limit: 10000K
    Total Submissions: 95209   Accepted: 38311

    Description

    One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instance, in the letter sequence ``DAABEC'', this measure is 5, since D is greater than four letters to its right and E is greater than one letter to its right. This measure is called the number of inversions in the sequence. The sequence ``AACEDGG'' has only one inversion (E and D)---it is nearly sorted---while the sequence ``ZWQM'' has 6 inversions (it is as unsorted as can be---exactly the reverse of sorted). 

    You are responsible for cataloguing a sequence of DNA strings (sequences containing only the four letters A, C, G, and T). However, you want to catalog them, not in alphabetical order, but rather in order of ``sortedness'', from ``most sorted'' to ``least sorted''. All the strings are of the same length. 

    Input

    The first line contains two integers: a positive integer n (0 < n <= 50) giving the length of the strings; and a positive integer m (0 < m <= 100) giving the number of strings. These are followed by m lines, each containing a string of length n.

    Output

    Output the list of input strings, arranged from ``most sorted'' to ``least sorted''. Since two strings can be equally sorted, then output them according to the orginal order.

    Sample Input

    10 6
    AACATGAAGG
    TTTTGGCCAA
    TTTGGCCAAA
    GATCAGATTT
    CCCGGGGGGA
    ATCGATGCAT

    Sample Output

    CCCGGGGGGA
    AACATGAAGG
    GATCAGATTT
    ATCGATGCAT
    TTTTGGCCAA
    TTTGGCCAAA

    C/C++代码

    #include <stdio.h>
    #include <string.h>
    #include <stdlib.h>
    
    struct Str{
        char str[51];
        int inversions;
    }data[100];
    
    int inversionNumber(char s[]) {
        
        int len = strlen(s);
        int result = 0;
        int A = 0, C = 0, G = 0;
        int i = len - 1;
        for(; i >= 0; i--)
            switch (s[i]) {
                case 'A':
                    A++;
                    break;
                case 'C':
                    result += A;
                    C++;
                    break;
                case 'G':
                    result = result + A + C;
                    G++;
                    break;
                case 'T':
                    result = result + A + C + G;
                    break;
                }
        return result;
    }
    
    int cmp(const void * a, const void * b) {
        
        struct Str* c = (struct Str *)a;
        struct Str* d = (struct Str *)b;
        return c->inversions - d->inversions;
        
    }
    
    int main(int argc, const char * argv[]) {
        
        int length, number;
        int i;
        scanf("%d%d", &length, &number);
    
        
        for (i = 0; i < number; i ++) {
            scanf("%s", data[i].str);
            data[i].inversions = inversionNumber(data[i].str);
        }
        
        qsort(data, number, sizeof(data[0]), cmp);
        
        for (i = 0; i < number; i ++) {
            printf("%s
    ", data[i].str);
        }
        
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/kkkkkk/p/5587800.html
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