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  • hdu 1057 A + B Again

    A + B Again

    • Problem Description

      There must be many A + B problems in our HDOJ , now a new one is coming.
      Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
      Easy ? AC it !

    • Input

      The input contains several test cases, please process to the end of the file.
      Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
      The length of A and B is less than 15.

    • Output

      For each test case,print the sum of A and B in hexadecimal in one line.

    • Sample Input

      +A -A
      +1A 12
      1A -9
      -1A -12
      1A -AA

    • Sample Output

      0
      2C
      11
      -2C
      -90

    题意:

    给两个16进制的数,计算两数和

    代码如下:

    #include<stdio.h>
    
    int main(void)
    {
        __int64 a, b;
    
        while(scanf("%I64x%I64X", &a, &b) != EOF)
            printf(a+b<0?"-%I64X
    ":"%I64X
    ", a+b<0?-a-b:a+b);
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/lanaiwanqi/p/10445737.html
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