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  • c语言学习笔记(6)——for和while循环

    for和while等价替换
    --------------------------
    int i = 1;
    for (i; i<=100; i++){
    sum = sum + 1;
    }
    --------------------------
    int i = 1;
    while(i<=100){
    sum = sum + 1;
    i++;
    }
    --------------------------
    从键盘输入一个数字,如果该数字是回文数,则返回yes,否则返回no
    回文数:正着写倒着写一样的数
    # include<stdio.h>


    int main(){
    int val, m, sum=0;
    printf("请输入您需要判断的数字:");
    scanf("%d", &val);

    m = val;
    while(m){
    sum = sum * 10 + m%10;
    m /= 10;
    }
    if(sum==val){
    printf("yes ");
    }else{
    printf("no ");
    }

    return 0;
    }
    --------------------------------------------------------------
    斐波拉器序列:
    1 2 3 5 8 13 21 34.....
    从第三项开始每一项是前两项的和
    # include <stdio.h>


    int main(void){
    int n;
    int f1, f2, f3;
    int i;


    f1 = 1;
    f2 = 2;

    printf("请输入您需要求得项的序列: ");
    scanf("%d", &n);


    if(1==n){
    f3 = 1;
    }else if(2==n){
    f3 = 2;
    }else{
    for(i=3; i<=n; i++){
    f3 = f1 + f2;
    f1 = f2;
    f2 = f3;
    }
    }
    printf("%d ", f3);
    return 0;
    }
    -----------------------------------------------------------------------
    do....while....实现一元二次方程
    do....while....至少执行一次
    # include <stdio.h>
    # include <math.h>


    int main(void)
    {
    double a, b, c;
    double delta;
    double x1, x2;
    char ch;

    do
    {
    printf("请输入一元二次方程的三个系数: ");
    printf("a = ");
    scanf("%lf", &a);

    printf("b = ");
    scanf("%lf", &b);

    printf("c = ");
    scanf("%lf", &c);

    delta = b*b - 4*a*c;

    if (delta > 0)
    {
    x1 = (-b + sqrt(delta)) / (2*a);
    x2 = (-b - sqrt(delta)) / (2*a);
    printf("有两个解,x1 = %lf, x2 = %lf ", x1, x2);
    }
    else if (0 == delta)
    {
    x1 = x2 = (-b) / (2*a);
    printf("有唯一解,x1 = x2 = %lf ", x1, x2);
    }
    else
    {
    printf("无实数解! ");
    }


    printf("您想继续么(Y/N): ");
    scanf(" %c", &ch);  //%c前面必须得加一个空格 原因略
    } while ('y'==ch || 'Y'==ch);

    return 0;
    }
    -----------------------------------------------------------------------
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  • 原文地址:https://www.cnblogs.com/lanzhi/p/6469928.html
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