简单题。递归。
/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean hasPathSum(TreeNode root, int sum) {
// Start typing your Java solution below
// DO NOT write main() function
if (root == null) {
return false;
}
if (root.left == null && root.right == null) {
return root.val == sum;
}
else {
return hasPathSum(root.left, sum-root.val) || hasPathSum(root.right, sum-root.val);
}
}
}