http://community.topcoder.com/stat?c=problem_statement&pm=11225&rd=14427
http://apps.topcoder.com/wiki/display/tc/SRM+498
此题的暴力解法是一个BFS。BFS的话,要有Queue,如果是图的话,还要有Set来记录走过的状态。后面答案中会看到其实可以用贪心,就是只要输入和输出的各种颜色数量一样,就一定能变换过来,这个下回再表。
import java.util.*;
public class NinePuzzle
{
public int getMinimumCost(String init, String goal)
{
int[][] arr = new int[10][];
arr[0] = new int[]{1, 2};
arr[1] = new int[]{0, 2, 3, 4};
arr[2] = new int[]{0, 1, 4, 5};
arr[3] = new int[]{1, 4, 6, 7};
arr[4] = new int[]{1, 2, 3, 5, 7, 8};
arr[5] = new int[]{2, 4, 8, 9};
arr[6] = new int[]{3, 7};
arr[7] = new int[]{3, 4, 6, 8};
arr[8] = new int[]{4, 5, 7, 9};
arr[9] = new int[]{5, 8};
Queue<String> queue = new LinkedList<String>();
HashSet<String> set = new HashSet<String>();
set.add(goal);
queue.offer(goal);
int initStar = -1;
for (int i = 0; i < init.length(); i++)
if (init.charAt(i) == '*')
initStar = i;
int ans = Integer.MAX_VALUE;
while (queue.size() != 0)
{
String s = queue.poll();
char[] ca = s.toCharArray();
int starPos = -1;
for (int i = 0; i < ca.length; i++)
if (ca[i] == '*') starPos = i;
if (initStar == starPos)
{
int a = 0;
for (int i = 0; i < s.length(); i++)
{
if (initStar != i && ca[i] != init.charAt(i)) a++;
}
if (ans > a) ans = a;
}
for (int i = 0; i < arr[starPos].length; i++)
{
swap(ca, starPos, arr[starPos][i]);
String tmp = new String(ca);
if (!set.contains(tmp))
{
queue.offer(tmp);
set.add(tmp);
}
swap(ca, starPos, arr[starPos][i]);
}
}
return ans;
}
private void swap(char[] ca, int i, int j)
{
char tmp = ca[i];
ca[i] = ca[j];
ca[j] = tmp;
}
}